提取与IP地址的字符串匹配的行 [英] extract a line that matches a string with IP address

问题描述

我正在使用python来查找与IP地址的特定模式匹配的行.

I am working on python to find a line that matches a particular pattern of an IP address.

f = open('file.txt','r')
for line in f:
    if line.find("N2:42.61.0.69")
        print line

我要匹配的模式是"node number":"IP address"，其中 "node number"是字母"N"，后跟数字".例如N23，N456，N98765等.

The pattern that I am trying to match is "node number":"IP address", where "node number" is the alphabet 'N' followed by a 'number'. Such as N23, N456, N98765, etc.

我使用了模式N2:42\.61\.0\.69，但是没有产生任何结果.

I used the pattern N2:42\.61\.0\.69, but it didn't yield any result.

大多数示例都讨论正则表达式以匹配特定模式，例如IP地址"^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$".

Most of the examples talks about regex to match a particular pattern such as for an IP address "^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$".

但是在这里，我要将特定字符串与IP地址匹配. 感谢您的帮助！

But here I want to match a particular string with IP address. Thanks for the help!

推荐答案

函数find():

返回在s中找到子字符串sub的最低索引，以使sub完全包含在s [start:end]中.失败时返回-1.起始和结束以及负值的解释默认值与切片相同.

Returns the lowest index in s where the substring sub is found such that sub is wholly contained in s[start:end]. Return -1 on failure. Defaults for start and end and interpretation of negative values is the same as for slices.

因此，如果要查找包含给定字符串(在您的情况下为"N2:42.61.0.69")的行，则条件应为:

So if you want to find lines containing the given string( "N2:42.61.0.69" in your case), the condition should be:

if line.find("N2:42.61.0.69") != -1:

这篇关于提取与IP地址的字符串匹配的行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！