UITableView在第一次加载时不响应滚动 [英] UITableView does not respond to scrolling the first time it's loaded

问题描述

我发现，第一次加载UITableView时，它不会对滚动触摸做出响应-如果它的行数不超过屏幕显示的容量.如果我关闭视图，则重新打开相同的对象-现在它会响应触摸-即使它包含相同数量的行.

I have found that the first time a UITableView loads, it does not respond to scrolling touches -- if it does not have more rows than fit on the screen. If I close the view, then reopen the same object -- it will now respond to touches -- even though it contains the same number of rows.

除了对行数响应UITableViewDataSource方法并自行生成行外，我没有做任何其他事情.每当视图出现时，我都会重新加载表.

I am not doing anything more than responding to the UITableViewDataSource methods for the number of rows, and generating the rows themselves. I am reloading the table every time the view appears.

任何人都可以解释这种行为吗?

Can anyone explain such behavior?

我正在像这样创建单元格:

I am creating the cells like so:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
  static NSString *tableId = @"NewIndexTableId";
  Note *note = [notes objectAtIndex:[indexPath row]];

  UITableViewCell *cell = [self.tableView dequeueReusableCellWithIdentifier:tableId];

  if (cell == nil)
    cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:tableId] autorelease];

  cell.textLabel.text = note.text;
  cell.detailTextLabel.text = [note changedDelta]; 
  cell.accessoryView = multipleAccounts ? [note.account imageView] : nil;

  return cell;  
}

推荐答案

我解决了此问题，方法是确保表中始终至少有10行-当实际行数少于10时创建虚拟行.这解决了故障.

I solved this problem by making sure there are always at least 10 rows in the table -- creating dummy rows when there are less than 10 real rows. This solved the glitch.

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