将Unichar转换为Int问题 [英] Converting Unichar to Int Problem

问题描述

尝试将unichar转换为int时遇到一个奇怪的问题:

I've got a strange problem trying to convert from unichar to int:

我有一个包含一些数字的字符串，例如@"12345".我要单独保存此数字，这意味着我需要5个数字，1、2、3，....现在，

I have a String containing a few numbers, like @"12345". This numbers I want to save individually, meaning I want 5 numbers, 1, 2, 3, ... . Now, while

NSLog(@"Value: %C", [myString characterAtIndex:0]);

返回

Value: 1

此:

NSLog(@"Value: %@", [NSNumber numberWithUnsignedChar:[myString characterAtIndex:0]]);

返回

Value: 49

真的很感谢Fabian

I would really appreciate some help, Fabian

推荐答案

在上面的代码中，您所得到的正是您想要的；字符'1'的数字值为49，您正在从中创建一个NSNumber.

In the code above, you're getting exactly what you're asking for; the numeric value of the character '1' is 49, and you're creating an NSNumber from that.

如果您想要的是1，则可以利用以下事实:将0-9数字按顺序排列在ASCII/UTF-8表中，并从收到的unichar中减去适当的值

If what you want is 1, then you can can take advantage of the fact that the digits 0-9 are laid out in order in the ASCII/UTF-8 tables and subtract an appropriate value from the unichar you receive.

请尝试以下代码片段，以帮助您正确地开始工作:

Try out this code snippet to get you started in the right direction:

NSString *s = @"0123456789";
for (int i = 0; i < [s length]; i++) {
    NSLog(@"Value: %d", [s characterAtIndex:i]);
}

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