使用python中的套接字建立IPv6连接 [英] Establishing an IPv6 connection using sockets in python

问题描述

我正在尝试运行这个非常基本的套接字示例:

I am trying to run this very basic socket example:

import socket
host = 'ipv6hostnamegoeshere'
port=9091

ourSocket = socket.socket(socket.AF_INET6, socket.SOCK_STREAM, 0)
ourSocket.connect((host, port))

但是，我得到了错误:

    ourSocket.connect((host, port))
  File "<string>", line 1, in connect
socket.error: [Errno 22] Invalid argument

布尔值has_ipv6返回true.有帮助吗?

The boolean has_ipv6 returns true. Any help?

推荐答案

作为

As the socket.connect docs says, AF_INET6 expects a 4-tuple:

sockaddr是一个描述 套接字地址，其格式取决于 在返回的家庭中(一个(地址， 端口)2个元组，用于AF_INET，(地址， 端口，流信息，作用域ID)4元组 AF_INET6)，并应通过 到socket.connect()方法.

sockaddr is a tuple describing a socket address, whose format depends on the returned family (a (address, port) 2-tuple for AF_INET, a (address, port, flow info, scope id) 4-tuple for AF_INET6), and is meant to be passed to the socket.connect() method.

例如:

>>> socket.getaddrinfo("www.python.org", 80, 0, 0, socket.SOL_TCP)
[(2, 1, 6, '', ('82.94.164.162', 80)),
 (10, 1, 6, '', ('2001:888:2000:d::a2', 80, 0, 0))]

>>> ourSocket = socket.socket(socket.AF_INET6, socket.SOCK_STREAM, 0)
>>> ourSocket.connect(('2001:888:2000:d::a2', 80, 0, 0))

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