在matplotlib图中显示原点轴(x，y) [英] show origin axis (x,y) in matplotlib plot

问题描述

我有一个简单的图，我想显示原点轴(x，y).我已经有网格了，但是我需要强调x，y轴.

I have following simple plot, and I would like to display the origin axis (x, y). I already have grid, but I need the x, y axis to be emphasized.

这是我的代码:

x = linspace(0.2,10,100)
plot(x, 1/x)
plot(x, log(x))
axis('equal')
grid()

我已经看到了这个问题.可接受的答案建议使用轴脊柱"，并仅链接到一些示例.但是，该示例使用子图过于复杂.我无法在我的简单示例中弄清楚如何使用轴脊柱".

I have seen this question. The accepted answer suggests to use "Axis spine" and just links to some example. The example is however too complicated, using subplots. I am unable to figure out, how to use "Axis spine" in my simple example.

推荐答案

使用subplots不太复杂，可能是棘刺.

Using subplots is not too complicated, the spines might be.

%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(0.2,10,100)
fig, ax = plt.subplots()
ax.plot(x, 1/x)
ax.plot(x, np.log(x))
ax.set_aspect('equal')
ax.grid(True, which='both')

ax.axhline(y=0, color='k')
ax.axvline(x=0, color='k')

我得到:

(由于x的下限为零，因此您看不到垂直轴.)

(you can't see the vertical axis since the lower x-limit is zero.)

%matplotlib inline
import numpy as np
import matplotlib.pyplot as plt

x = np.linspace(0.2,10,100)
fig, ax = plt.subplots()
ax.plot(x, 1/x)
ax.plot(x, np.log(x))
ax.set_aspect('equal')
ax.grid(True, which='both')

# set the x-spine (see below for more info on `set_position`)
ax.spines['left'].set_position('zero')

# turn off the right spine/ticks
ax.spines['right'].set_color('none')
ax.yaxis.tick_left()

# set the y-spine
ax.spines['bottom'].set_position('zero')

# turn off the top spine/ticks
ax.spines['top'].set_color('none')
ax.xaxis.tick_bottom()

import numpy as np
import matplotlib.pyplot as plt
import seaborn
seaborn.set(style='ticks')

x = np.linspace(0.2,10,100)
fig, ax = plt.subplots()
ax.plot(x, 1/x)
ax.plot(x, np.log(x))
ax.set_aspect('equal')
ax.grid(True, which='both')
seaborn.despine(ax=ax, offset=0) # the important part here

以下是 set_position方法的文档的文档:

Here are the docs for a the set_position method of spines:

脊柱位置由2个元组(位置类型，数量)指定. 职位类型为:

Spine position is specified by a 2 tuple of (position type, amount). The position types are:

• 'outward':将书脊从数据区域中移出指定的点数. (负值指定放置
  脊椎向内.)

• 'outward' : place the spine out from the data area by the specified number of points. (Negative values specify placing the
  spine inward.)

'axes':将书脊放置在指定的Axes坐标处(从 0.0-1.0).

'axes' : place the spine at the specified Axes coordinate (from 0.0-1.0).

数据":将书脊放置在指定的数据坐标处.

'data' : place the spine at the specified data coordinate.

此外，速记符号定义了特殊位置:

Additionally, shorthand notations define a special positions:

• 'center'->('axes'，0.5)
• '零'->('数据'，0.0)

因此，您可以使用以下任何一种方法放置左脊椎:

So you can place, say the left spine anywhere with:

ax.spines['left'].set_position((system, poisition))

其中system是向外"，轴"或数据"，而position在该坐标系中的位置.

where system is 'outward', 'axes', or 'data' and position in the place in that coordinate system.

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