“只能迭代". Python错误 [英] "Can only iterable" Python error

问题描述

你好，我的程序员们.

我是一个相当新的程序员，现在我面临着巨大的困境.我收到错误消息:

can only assign an iterable

首先我不知道那是什么意思.

第二，我将我的代码留给您的专业人员进行批判:

def num_top(int_lis):
    duplic_int_lis = int_lis
    int_firs= duplic_int_lis [0]
    int_lis[:] = duplic_int_lis [int_firs]

基本上，我试图在列表中找到[0]元素，然后使用该int作为索引位置来找到该索引位置处的整数.

解决方案

int_lis[:] = duplic_int_lis [int_firs]意味着将duplic_int_lis [int_firs]的所有项分配给int_lis，因此希望您在RHS上传递可迭代/迭代器.

但是在您的情况下，您将其传递为不可迭代的，这是不正确的:

>>> lis = range(10)
>>> lis[:] = range(5) 
>>> lis               #all items of `lis` replaced with range(5)
[0, 1, 2, 3, 4]

>>> lis[:] = 5        #Non-iterable will raise an error.
Traceback (most recent call last):
  File "<ipython-input-77-0704f8a4410d>", line 1, in <module>
    lis[:] = 5
TypeError: can only assign an iterable

>>> lis[:] = 'foobar' #works for any iterable/iterator
>>> lis
['f', 'o', 'o', 'b', 'a', 'r']

由于您不能迭代整数，因此会出现错误.

>>> for x in 1: pass
Traceback (most recent call last):
  File "<ipython-input-84-416802313c58>", line 1, in <module>
    for x in 1:pass
TypeError: 'int' object is not iterable

Hello my fellow programmers.

I am a fairly new programmer, and now I am facing a great predicament. I am getting the error:

can only assign an iterable

Firstly I don't know what that means.

Secondly I will leave my code for you professionals to critique it:

def num_top(int_lis):
    duplic_int_lis = int_lis
    int_firs= duplic_int_lis [0]
    int_lis[:] = duplic_int_lis [int_firs]

Basically I am trying to find the [0] element in the list and then using that int as an index position to find the integer at that index position.

解决方案

int_lis[:] = duplic_int_lis [int_firs] means assign all the items of duplic_int_lis [int_firs] to int_lis, so it expects you to pass an iterable/iterator on the RHS.

But in your case you're passing it an non-iterable, which is incorrect:

>>> lis = range(10)
>>> lis[:] = range(5) 
>>> lis               #all items of `lis` replaced with range(5)
[0, 1, 2, 3, 4]

>>> lis[:] = 5        #Non-iterable will raise an error.
Traceback (most recent call last):
  File "<ipython-input-77-0704f8a4410d>", line 1, in <module>
    lis[:] = 5
TypeError: can only assign an iterable

>>> lis[:] = 'foobar' #works for any iterable/iterator
>>> lis
['f', 'o', 'o', 'b', 'a', 'r']

As you cannot iterate over an integer, hence the error.

>>> for x in 1: pass
Traceback (most recent call last):
  File "<ipython-input-84-416802313c58>", line 1, in <module>
    for x in 1:pass
TypeError: 'int' object is not iterable

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