在Java中使用Jackson来创建JSON对象 [英] Create JSON object using Jackson in Java
本文介绍了在Java中使用Jackson来创建JSON对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我需要使用Jackson如下创建一个JSON字符串. 我知道已经在这里回答了类似的问题:使用杰克逊创建json对象
I need to create a JSON string as below using Jackson. I know similar question has been answered already here: Creating a json object using jackson
但是我期望的JSON字符串与上面的示例有些不同.
But my expected JSON string is a little different from the one in above example.
如何仅使用Jackson来在Java中形成以下格式化的JSON对象? 另外,我不希望创建单独的POJO来实现此目的.
How can I form the below formatted JSON object in Java using only Jackson? Also, I do not prefer creating a separate POJO to achieve this.
预期输出:
{
"obj1": {
"name1": "val1",
"name2": "val2"
},
"obj2": {
"name3": "val3",
"name4": "val4"
},
"obj3": {
"name5": "val5",
"name6": "val6"
}
}
推荐答案
尝试一下:
ObjectMapper mapper = new ObjectMapper();
ObjectNode rootNode = mapper.createObjectNode();
ObjectNode childNode1 = mapper.createObjectNode();
childNode1.put("name1", "val1");
childNode1.put("name2", "val2");
rootNode.set("obj1", childNode1);
ObjectNode childNode2 = mapper.createObjectNode();
childNode2.put("name3", "val3");
childNode2.put("name4", "val4");
rootNode.set("obj2", childNode2);
ObjectNode childNode3 = mapper.createObjectNode();
childNode3.put("name5", "val5");
childNode3.put("name6", "val6");
rootNode.set("obj3", childNode3);
String jsonString = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(rootNode);
System.out.println(jsonString);
这篇关于在Java中使用Jackson来创建JSON对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文