如何为我的自定义@Query返回的列值创建自定义json对象 [英] How to create a custom json object to columns value returned from my custom @Query

问题描述

我对My SQL数据库有一个查询，我使用Spring Boot将其返回为Json格式. 我的问题是它只返回没有键的值，如:

I have a query to My SQL database and I use Spring Boot to return it to Json format. My problem is it only return value without key like:

[
  [
    "kermit",
    6
  ]
]

我希望它返回:

[
  [
    "name":"kermit",
     "count" :6
  ]
]

我尝试将Jackson注释jar文件添加到项目中，并在我的实体模型类中使用@JsonProperty:

I tried add Jackson Annotation jar file to project and use @JsonProperty in my entity model class:

@Entity
@Table(name = "act_id_membership", schema = "activiti", catalog = "")
@IdClass(ActIdMembershipEntityPK.class)
public class ActIdMembershipEntity {

    @JsonProperty("name")
    private String userId;

    @JsonProperty("group")
    private String groupId;

    @Id
    @Column(name = "USER_ID_")
    public String getUserId() {
        return userId;
    }

    public void setUserId(String userId) {
        this.userId = userId;
    }

    @Id
    @Column(name = "GROUP_ID_")
    public String getGroupId() {
        return groupId;
    }

    public void setGroupId(String groupId) {
        this.groupId = groupId;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (o == null || getClass() != o.getClass()) return false;
        ActIdMembershipEntity that = (ActIdMembershipEntity) o;
        return Objects.equals(userId, that.userId) &&
                Objects.equals(groupId, that.groupId);
    }

    @Override
    public int hashCode() {
        return Objects.hash(userId, groupId);
    }
}

但是它仍然没有密钥返回.我现在该怎么办?请帮我！ 非常感谢你！

But it still return without key. What I should do now? Please help me! Thank you very much!

推荐答案

首先，我同意那些评论无效JSON格式的人.您可以在此处查看示例 https://json.org/example.html

First, I'm agree with guy who commented that is not valid JSON format. You can see examples here https://json.org/example.html

第二，您需要创建一个对象JSON，其中包含所需的字段，例如:

Second, You need to create an object JSON which has fields needed for example:

  public class UserStat es implements Serializable {

         private String name;
         private long count;

         public String getName() {
             return name;
         } 

         public void setName(String name) {
             this.name = name;
         } 

         public long getCount() {
             return count;
         } 

         public void setCount(long count) {
             this.count = count;
         } 
  }

并在您的自定义查询中.根据这种方式，您的报酬看起来像这样:

And in your custom query. Based your return looks like on this way:

  @Query("SELECT u.name, count(u) FROM User u")
   public List<UserStat> findUserStat() ;

这篇关于如何为我的自定义@Query返回的列值创建自定义json对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！