使用Jackson序列化Java中的数组数组 [英] Serializing an array of arrays in java using Jackson
本文介绍了使用Jackson序列化Java中的数组数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在学习如何使用Jackson,并且必须序列化一系列ContoCorrente对象
I'm learning how to use Jackson and I have to serialize an array of ContoCorrente objects
public class ContoCorrente {
private String proprietario;
private ArrayList<MovimentoBancario> movimenti;
//methods...
}
其中MovimentoBancario定义为
where MovimentoBancario is defined as
public class MovimentoBancario {
private String data;
private String causale;
//methods...
}
我尝试过
ArrayList<ContoCorrente> conti= new ArrayList<ContoCorrente>(50);
for(int i=0; i<50; i++){
//fill array
}
try {
ObjectMapper mapper = new ObjectMapper();
mapper.configure(SerializationFeature.FAIL_ON_EMPTY_BEANS, false);
System.out.println(mapper.writeValueAsString(conti));
} catch (Exception e) {
e.printStackTrace();
}
但输出是
[{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{},{}]
我不知道我在做什么错,这是我第一次尝试序列化
I don't know what I'm doing wrong, it's the first time I try serialization
推荐答案
您可以尝试使用Jackson定义特定方法.
You can try defining a specific method using Jackson.
private static final ObjectMapper objectMapper = new ObjectMapper();
private static final ObjectReader reader = new ObjectMapper().readerFor(Array.class);
public static String toArray(ArrayList<ContoCorrente> array) throws JsonProcessingException {
return objectMapper.writeValueAsString(array);
}
然后,如果您想阅读,请使用阅读器.
Then if you want to read just use the reader.
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