从单独的jar调用.asSubclass时引发ClassCastException [英] ClassCastException thrown when calling .asSubclass from separate jar

查看:66
本文介绍了从单独的jar调用.asSubclass时引发ClassCastException的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个程序,可以通过它完成以下三个课程.前两个在jar1.jar中:

I have a program through which I have the following three classes. These first two are in jar1.jar:

Main(使用在此处找到的jar加载技巧):

Main (uses the jar loading trick found here):

package prob1;

import java.io.IOException;
import java.net.URL;
import java.net.URLClassLoader;
import java.util.ArrayList;
import java.util.Enumeration;
import java.util.List;
import java.util.jar.JarEntry;
import java.util.jar.JarFile;

public class Main {
    static List<Class<?>> classes = new ArrayList<Class<?>>();

    static String pathToJar = "/Users/vtcakavsmoace/Desktop/jar2.jar";

    public static void main(String[] args) throws ClassNotFoundException, IOException, InstantiationException, IllegalAccessException {
        loadJar();

        classes.get(0).asSubclass(A.class).newInstance().someMethod();
    }

    private static void loadJar() throws IOException, ClassNotFoundException {
        JarFile jarFile = new JarFile(pathToJar);
        Enumeration<JarEntry> e = jarFile.entries();

        URL[] urls = { new URL("jar:file:" + pathToJar + "!/") };
        URLClassLoader cl = URLClassLoader.newInstance(urls);

        while (e.hasMoreElements()) {
            JarEntry je = e.nextElement();
            if (je.isDirectory() || !je.getName().endsWith(".class")) {
                continue;
            }

            String className = je.getName().substring(0, je.getName().length() - 6);
            className = className.replace('/', '.');
            classes.add(cl.loadClass(className));
        }

        jarFile.close();
    }
}

A:

package prob1;

public interface A {
    void someMethod();
}

以及在jar2.jarB中找到的第二个类:

And a second class found in jar2.jar, B:

package prob2;

import prob1.A;

public class B implements A {

    @Override
    public void someMethod() {
        System.out.println("Hello, world!");
    }

}

如您所见,类B显然实现了接口A.但是,在加载类B并尝试在其上调用asSubclass时,失败,并带有以下异常:

As you can see, class B obviously implements interface A. However, when loading class B, and then attempting to call asSubclass on it, fails with the following exception:

Exception in thread "main" java.lang.reflect.InvocationTargetException
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:497)
    at org.eclipse.jdt.internal.jarinjarloader.JarRsrcLoader.main(JarRsrcLoader.java:58)
Caused by: java.lang.ClassCastException: class prob2.B
    at java.lang.Class.asSubclass(Class.java:3404)
    at prob1.Main.main(Main.java:20)
    ... 5 more

请注意,通过Eclipse运行时这不会失败.

Note that this does not fail when run through Eclipse.

我在这里做错了什么?我该如何解决?

What am I doing wrong here? How can I fix this?

推荐答案

好吧,使用 Erwin Bolwidt的知识找到了答案给了我;在Main类中,替换为:

Okay, found the answer using the knowledge that Erwin Bolwidt gave me; in class Main, replacing:

URLClassLoader cl = URLClassLoader.newInstance(urls);

具有:

URLClassLoader cl = URLClassLoader.newInstance(urls, Main.class.getClassLoader());

解决此问题. :P

这篇关于从单独的jar调用.asSubclass时引发ClassCastException的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆