如果语句被调用一次后又跳到其他语句? [英] If statement skipping right to else after being called once?
本文介绍了如果语句被调用一次后又跳到其他语句?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在做一个简单的抛硬币游戏,我写了几种方法来调用并使我的主类简短而简单.游戏播放一次后,第一个要求用户输入的If/Else语句将直接跳到Else语句,而不会提示输入.
I'm making a simple coin toss game, and I wrote several methods to call and make my main class short and simple. After the game is played once, the first If/Else statement to ask users for input is jumping right to the Else statement without prompting for input.
package cointoss;
import java.util.Random;
import java.util.Scanner;
public class Game {
int money;
int result;
int bet;
Random rn = new Random();
Scanner in = new Scanner(System.in);
String playerPick;
String aResult;
public void setMoney(int a)
{
money = a;
}
public int getMoney()
{
return money;
}
public void getBet()
{
System.out.println("How much would you like to bet?");
bet = in.nextInt();
do{
if(bet > money)
{
System.out.println("You cannot bet more than you have!");
System.out.println("You have bet " + (bet - money) + " too many coins.");
continue;
}
else
System.out.println("You have bet " + bet + " coins.");
}
while(bet > money);
}
public void getInput()
{
System.out.println("Pick Heads or Tails");
playerPick = in.nextLine();
playerPick.toLowerCase();
if(playerPick.contains("heads"))
playerPick ="heads";
else if(playerPick.contains("tails"))
playerPick ="tails";
else
System.out.println("Invalid Selection");
}
public void flipCoin()
{
result = rn.nextInt(2);
if(result == 0)
{
aResult = "heads";
}
else
aResult = "tails";
}
public void checkResult()
{
if(playerPick.equals(aResult))
{
System.out.println("You have won!");
money += bet;
System.out.println("You now have " + money + " coins");
}
else{
System.out.println("You have lost!");
money -= bet;
System.out.println("You now have " + money + " coins");
}
}
}
我的测试人员课程:
package cointoss;
public class GameTest {
public static void main(String[] args)
{
Game coinToss = new Game();
coinToss.setMoney(100);
while(coinToss.getMoney() > 0)
{
coinToss.getInput();
coinToss.getBet();
coinToss.flipCoin();
coinToss.checkResult();
}
}
}
推荐答案
您的问题是,每次运行测试程序循环时,您都没有将"in"初始化为新的扫描程序.单个扫描器读取一行输入并将其作为完整答案,而不确认可能还会有其他输入.
Your problem is that you are not reinitializing "in" as a new Scanner every time you run the tester loop. The single scanner reads a line of input and accepts that as the full answer, without acknowledging that there could be further input.
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