在运行Java 7的STS上打开New Spring Starter Project向导时，出现SocketTimeoutException [英] SocketTimeoutException while opening New Spring Starter Project wizard on STS running with Java 7

问题描述

我将STS 3.5.1的ZIP发行版用于Win32. 我使用以下cmd脚本启动STS:

I'm using the ZIP distribution of STS 3.5.1 for win32. I start STS with this cmd script:

set JAVA_HOME=d:\jdk\jdk1.7.0_21
set PATH=%JAVA_HOME%\bin;%PATH%;
start .\sts-3.5.1.RELEASE\sts.exe

然后，当我执行新建> Spring Starter项目"时，出现此错误:

Then, when I do "New > Spring Starter Project", I get this error:

如果通过更改cmd脚本的第一行将Java 7替换为Java 7，一切正常:向导启动.

If I replace Java 7 with Java 6 by changing the first line of my cmd script, everything works fine: the wizard starts.

set JAVA_HOME=d:\jdk\jdk1.6.0_31

如果我想使用Java 7，有什么特别的事情要做吗?

Is there something special to do if I want to use Java 7 ?

推荐答案

您可能希望获得JDK 1.7的最新版本(例如1.7.0_51)，因为早期版本中存在许多令人不愉快的错误.否则我没有任何建议.您可以从浏览器中看到该服务( http://start.spring.io )吗?

You probably want to get a more recent version of the JDK 1.7 (e.g. 1.7.0_51) as there were quite a few unpleasant bugs in earlier releases. Otherwise I don't have any suggestions. Can you see the service (http://start.spring.io) from your browser?

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