根据Integerlist过滤对象列表 [英] Filter an object list based on Integerlist

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本文介绍了根据Integerlist过滤对象列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个类似的课程

class Employee
  String id
  String name

我想根据作为整数列表的deptId列表过滤出员工列表

I want to filter out the list of employees based on the list of deptId which is an integer list

Employee emp1 = new Employee("1","Ally");
Employee emp2 = new Employee("2","Billy");
ArrayList<Employee> employeeList = Arrays.asList(emp1,emp2);
ArrayList<Integer> ids = Arrays.asList(2);

我写的是

List<Employee> filteredList = employeeList.stream()
  .filter(employee -> ids.contains(employee.getId()))
  .collect(Collectors.toList());

但是作为输出,我得到了一个空数组.

But as an output I get an empty array.

推荐答案

首先,您需要将subscription更改为employee.

First, you need to change subscription to employee.

将ID列表更改为Strings列表并进行相应填充,或执行以下操作:

Either change your ID list to a list of Strings and populate accordingly or do something like this:

List<Employee> filteredList;
filteredList = employeeList.stream()
     .filter(employee -> ids.contains(Integer.parseInt(employee.getId())))
     .collect(Collectors.toList());

其他选项包括将您的Employee类更改为使用int作为ID.

Other options include changing your Employee class to use an int as an id.

这篇关于根据Integerlist过滤对象列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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