Java 8 LocalDateTime和DateTimeFormatter [英] Java 8 LocalDateTime and DateTimeFormatter

问题描述

在下面的一段代码中解决了异常..我在这里做错什么了吗?

below piece of code thorws exception..am i doing something wrong here?

DateTimeFormatter  FORMATTER    = DateTimeFormatter.ofPattern(
                                        "ddMMuuuuHHmmssSSS"
                                    );      
    String currentTime=FORMATTER.format(LocalDateTime.now());
    System.out.println(currentTime);
    LocalDateTime parsedTime=LocalDateTime.parse(currentTime,FORMATTER);


09042016161444380
Exception in thread "main" java.time.format.DateTimeParseException: Text '09042016161444380' could not be parsed at index 4
at java.time.format.DateTimeFormatter.parseResolved0(DateTimeFormatter.java:1949)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1851)
at java.time.LocalDateTime.parse(LocalDateTime.java:492)

推荐答案

如上面提到的 Jon Skeet 注释，使用uuuu，解析器不知道年份将在何处停止.这是因为解析器从字面上解释了2个以上的u's或y's.

As Jon Skeet mentioned in the above comment, with uuuu the parser doesn't know where the year is going to stop. This is because more than 2 u's or y's are interpreted literally by the parser.

来自Year的JavaDoc:

From JavaDoc of Year:

对于解析，如果模式字母的数量大于2，则将按字面意义解释年份，而不考虑数字的数量.因此，使用模式"MM/dd/yyyy"，"01/11/12"解析为公元1月11日

For parsing, if the number of pattern letters is more than 2, the year is interpreted literally, regardless of the number of digits. So using the pattern "MM/dd/yyyy", "01/11/12" parses to Jan 11, 12 A.D.

因此，如果将其从ddMMuuuuHHmmssSSS更改为ddMMuuHHmmssSSS或ddMMyyHHmmssSSS，它应该可以正常工作，因为在这种情况下，解析器知道确切的停止位置.

Hence, it should work fine if you change it to ddMMuuHHmmssSSS or ddMMyyHHmmssSSS from ddMMuuuuHHmmssSSS as in this instance the parser knows where to stop exactly.

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