Java Streams中的lambda函数集合 [英] Collection of lambda functions in Java Streams

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本文介绍了Java Streams中的lambda函数集合的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个流功能KStream<K, V>[] branch(final Predicate<? super K, ? super V>... predicates).我想动态创建谓词列表.有可能吗?

I have a stream function KStream<K, V>[] branch(final Predicate<? super K, ? super V>... predicates). I wanted to create a list of predicates dynamically. Is that possible?

       KStream<Long, AccountMigrationEvent>[] branches = stream
           .map((key, event) -> enrich(key, event))
           .branch(getStrategies());

        [...]

        private List<org.apache.kafka.streams.kstream.Predicate<Long, AccountMigrationEvent>> getStrategies() {
            ArrayList<Predicate<Long, AccountMigrationEvent>> predicates = new ArrayList<>();
            for (MigrationStrategy strategy : strategies) {
                predicates.add(new org.apache.kafka.streams.kstream.Predicate<Long, AccountMigrationEvent>() {
                    @Override
                    public boolean test(Long key, AccountMigrationEvent value) {
                        return strategy.match(value);
                    }
                });

            }
            return predicates;
        }

推荐答案

我尚未测试此代码,但从理论上讲,它应该可以工作:

I haven't tested this code but in theory it should work:

//All the predicates mentioned in here are of type org.apache.kafka.streams.kstream.Predicate
private Predicate<Long, AccountMigrationEvent>>[] getStrategies() {

  List<Predicate<Long, AccountMigrationEvent>> predicates = strategies.stream()
            .map(strategy -> (Predicate<Long, AccountMigrationEvent>>) (key, value) -> strategy.matches(value))
            .collect(toList());

    // branch() method on KStream requires an array so we need to transform our list
    return predicates.toArray(new Predicate[predicates.size()]);
}

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