如何在JavaFX中使未修饰的窗口可移动/可拖动? [英] How to make an undecorated window movable / draggable in JavaFX?
问题描述
我必须创建一个将禁用最小化"和最大化"按钮的应用程序.
I have to create an application in which minimize and maximize button will be disabled.
我使用了"StageStyle.UNDECORATED"
,该应用程序将不再可移动或拖动,因此我正在寻找其他任何替代方法来制作我的应用程序.
I have used "StageStyle.UNDECORATED"
with which the application will not be movable or draggable anymore, so I am searching for any other alternative to make my application.
有人对此有解决方案吗?
Do anyone having solution for this?
推荐答案
要使窗口无装饰但仍可移动/可拖动,您必须在您选择的任何节点上处理适当的MouseEvent
.
To achieve the window to be undecorated but still movable/dragable you have to handle the appropriate MouseEvent
on any node of your choice.
示例:
import javafx.application.Application;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.input.MouseEvent;
import javafx.scene.layout.BorderPane;
import javafx.stage.Stage;
import javafx.stage.StageStyle;
public class SimpleWindowApplication extends Application {
private double xOffset = 0;
private double yOffset = 0;
public static void main(String[] args) {
launch(args);
}
@Override
public void start(final Stage primaryStage) {
primaryStage.initStyle(StageStyle.UNDECORATED);
BorderPane root = new BorderPane();
root.setOnMousePressed(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
xOffset = event.getSceneX();
yOffset = event.getSceneY();
}
});
root.setOnMouseDragged(new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent event) {
primaryStage.setX(event.getScreenX() - xOffset);
primaryStage.setY(event.getScreenY() - yOffset);
}
});
Scene scene = new Scene(root, 800, 600);
primaryStage.setScene(scene);
primaryStage.show();
}
}
从Oracle JavaFX下载页面上包含的非常有价值的示例中了解更多信息: JavaFX演示和示例
Learn more from the very valuable examples contained on Oracle's JavaFX download page under: JavaFX Demos and Samples
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