为什么JavaFX Application.launch()将class作为参数? [英] Why JavaFX Application.launch() takes class as an argument?

问题描述

我是javaFx的新手，对源代码有些了解，并对以下问题有所疑问 用于启动应用程序的Application.launch函数.

I'm new to javaFx and looked a bit into source code and have a question regarding Application.launch function that is used to start an app.

签名如下:

public static void launch(Class<? extends Application> appClass, String... args)

我的问题是为什么它看起来不是这样:

And my question is why it doesn't look like this:

 public static void launch(Application app, String... args)

作者以课堂为论点试图达到什么目的?

What authors try to achieve by taking class as an argument?

推荐答案

因为Application的实例化是一项复杂的任务，FX开发人员必须对此进行控制.

Because an instantiation of the Application is a complex task which FX developers have to have the control over.

Application实例:

• 需要"FX工具箱"进行预先初始化
• 针对桌面，jnlp和插件模式而有所不同
• 需要特定的时间
• 应在特殊的启动器"线程上调用
• 应触发应用程序生命周期事件
• 应从CLI或jnlp文件读取应用程序参数

因此，您仅提供要启动的类名，而JavaFX会完成所需的所有工作，包括为您创建一个对象.

Thus you provide only class name to launch and JavaFX do all the work required, including creating an object for you.

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