从JavaFX打开外部应用程序 [英] Open External Application From JavaFX

问题描述

我找到了一种使用HostServices在默认浏览器中打开链接的方法.

I found a way to open a link on default browser using HostServices.

getHostServices().showDocument("http://www.google.com");

• 有什么方法可以在默认媒体播放器中打开媒体吗?
• 是否可以启动特定的文件或应用程序?
• Is there any way to open a media in default media player?
• Is there any way to launch a specific File or Application?

推荐答案

如果要在浏览器中打开具有http:方案的URL，或者使用该文件类型的默认应用程序打开文件，您引用的HostServices.showDocument(...)方法提供了一种纯JavaFX"方法.请注意，就我所知，您不能使用它来从Web服务器下载文件并使用默认应用程序将其打开.

If you want to either open a URL which has an http: scheme in the browser, or open a file using the default application for that file type, the HostServices.showDocument(...) method you referenced provides a "pure JavaFX" way to do this. Note that you can't use this (as far as I can tell) to download a file from a web server and open it with the default application.

要使用默认应用程序打开文件，必须将文件转换为file: URL的字符串表示形式.这是一个简单的示例:

To open a file with the default application, you must convert the file to the string representation of the file: URL. Here is a simple example:

import java.io.File;

import javafx.application.Application;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.geometry.Insets;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.Label;
import javafx.scene.control.TextField;
import javafx.scene.layout.HBox;
import javafx.scene.layout.VBox;
import javafx.stage.FileChooser;
import javafx.stage.Stage;

public class OpenResourceNatively extends Application {

    @Override
    public void start(Stage primaryStage) {
        TextField textField = new TextField("http://stackoverflow.com/questions/39898704");
        Button openURLButton = new Button("Open URL");
        EventHandler<ActionEvent> handler = e -> open(textField.getText());
        textField.setOnAction(handler);
        openURLButton.setOnAction(handler);

        FileChooser fileChooser = new FileChooser();
        Button openFileButton = new Button("Open File...");
        openFileButton.setOnAction(e -> {
            File file = fileChooser.showOpenDialog(primaryStage);
            if (file != null) {
                open(file.toURI().toString());
            }
        });

        VBox root = new VBox(5, 
                new HBox(new Label("URL:"), textField, openURLButton),
                new HBox(openFileButton)
        );

        root.setPadding(new Insets(20));
        primaryStage.setScene(new Scene(root));
        primaryStage.show();
    }

    private void open(String resource) {
        getHostServices().showDocument(resource);
    }

    public static void main(String[] args) {
        launch(args);
    }
}

这篇关于从JavaFX打开外部应用程序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！