javascript推送返回数字而不是对象 [英] javascript push returning number instead of object

问题描述

我确定这只是我所缺少的一个简单而愚蠢的错误，但是有人可以告诉我为什么返回3而不是[{ "method": 'popup', "minutes": ''}, {"method": 'email', "minutes": '10'}, {"method": 'popup', "minutes": '20'}];吗?

I'm sure this is just some simple silly mistake that I'm missing, but can anyone tell me why 3 is being returned instead of [{ "method": 'popup', "minutes": ''}, {"method": 'email', "minutes": '10'}, {"method": 'popup', "minutes": '20'}];?

我制作了一个jsfiddle，因此您也可以看到: https://jsfiddle.net/qk10arb0/3/

I made a jsfiddle so you can see as well: https://jsfiddle.net/qk10arb0/3/

HTML

<p>Click the button to add a new element to the array.</p>

<button onclick="addNewReminder()">Try it</button>

<p id="demo"></p>

JavaScript

function addNewReminder(){
      var newReminder = {
        "method": 'popup',
        "minutes": '20'
      };

      var reminders = [{
                "method": 'popup',
                "minutes": ''
              }, {
                  "method": 'email',
                  "minutes": '10'
              }];

    reminders = reminders.push(newReminder);
    document.getElementById("demo").innerHTML = reminders;
}

谢谢！

推荐答案

Array#push方法在原位运行，您不必将其分配给新变量.它不会返回新数组，但会修改原始数组并返回length.这就是为什么您得到3作为结果的原因.

Array#push method works in situ, you don't have to assign it to a new variable. It won't return a new array, but will modify the original one and will return it's length. That's why you are getting 3 as the result.

要获得所需的结果，只需调用它，而不分配任何变量:

To get the desired result, just call it, without assigning to any variable:

reminders.push(newReminder);

这篇关于javascript推送返回数字而不是对象的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！