删除嵌套javascript对象中的空值 [英] Delete null values in nested javascript objects

问题描述

我有一个嵌套的对象，并且想要删除所有键/值对，如果值是null或未定义.我设法使下面的代码正常工作，但是它没有检查嵌套的键/值对，并想知道是否有人可以帮助我找出需要添加到代码中的内容?

I have a nested object and want to remove all key/value pairs if the value is null or undefined. I've managed to get the below code working but it doesn't check the nested key/value pairs and wondered if someone could help me figure out what needs adding to the code please?

var myObj = {
  fName:'john',
  lName:'doe',
  dob:{
    displayValue: null, 
    value: null
  },
  bbb:null
};

function clean(obj) {
  for (var propName in obj) { 
    if (obj[propName] === null || obj[propName] === undefined || obj[propName] === '') {
      delete obj[propName];
    }
  }
  return obj;
}
console.log(clean(myObj));

上面的代码完成了删除"bbb"及其值的工作，我也希望对以"dob"表示的嵌套对象执行相同的操作.

The above code does the job to remove 'bbb' and its value and I want the same done for the nested object represented by 'dob' as well.

https://jsbin.com/mudirateso/edit?js,console,output

任何帮助将不胜感激.

Any help is greatly appreciated.

推荐答案

您已经快要准备好了.如果该属性是另一个对象，只需让函数递归:

You're already almost there. Just have the function recurse if the property is another object:

var myObj = {
  fName:'john',
  lName:'doe',
  dob:{
    displayValue: null, 
    value: null
  },
  bbb:null
};

function clean(obj) {
  for (var propName in obj) { 
    if (obj[propName] === null || obj[propName] === undefined || obj[propName] === '') {
      delete obj[propName];
    } else if (typeof obj[propName] === "object") {
      // Recurse here if the property is another object.
      clean(obj[propName])
    }
  }
  return obj;
}
console.log(clean(myObj));

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