Java 8:将IntStream转换为Integer [] [英] Java 8: IntStream to Integer[]

问题描述

我正在编写一个简单的程序，该程序最终将绘制用Java编写的各种排序算法的运行时间.排序算法的常规接口通过以下方法:public void sort(Comparable[] xs)

I am writing simple program which will eventually plot the run times of various sorting algorithms written in Java. The general interface of a sorting algorithm is via a method: public void sort(Comparable[] xs)

我正在尝试使用Java 8的流机制按照以下几行生成随机测试用例:

I am attempting to use Java 8's stream mechanism to generate random test cases along the following lines:

public static IntStream testCase(int min, int max, int n) {
    Random generator = new Random();
    return generator.ints(min, max).limit(n);
}

我的问题是，如何将类型为IntStream的对象转换为Integer[]?

My question is, how can I convert an object of type IntStream to an Integer[]?

推荐答案

您应

You should box the IntStream to a Stream<Integer>, then call toArray to make a array of it:

Integer[] arr = testCase(1,2,3).boxed().toArray(Integer[]::new);

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