Unmarshal对象内的Java循环 [英] Java loop inside Unmarshal object

问题描述

在此链接上: JAXB解组XML字符串-遍历所有标签 提出了一个好的解决方案. 我正在尝试从中受益，但无法使其适用于我的情况.

At this link: JAXB Unmarshalling XML string - Looping through all tags it was proposed a good solution. I'm trying to benefit from it but I am not able to have it working in my case.

考虑这样的XML:

<campaign value="field1">
  <name value="firstName"/>
  <type value="type"/>
  <record>
    <firstTime value="13"/>
    <secondTime value="14"/>
  </record>
</campaign>

并考虑解组，创建和工作的所有类. 广告系列类别，包含名称，值，记录[]等.

And consider all the classes for Unmarshalling, created and working. campaign class, containing name, value, record[] etc.

JAXBContext c = JAXBContext.newInstance(Campaign.class);
Unmarshaller u = c.createUnmarshaller();
Campaign campaign = (Campaign) u.unmarshal(file);

我可以提取名称"和类型"的值，但是由于列表的原因，我无法超出此范围.

I can extract the value of "name" and "type" but, because of the List<>, I am not able to go beyond this.

private String Name = null;
[...]
Name = campaign.getName().getValue();
System.out.println(Name);

知道其他XML文件中可能还有更多<record>的情况下，如何循环进入<record>，并获取firstTime和secondTime的所有值?

How would you loop into <record>, and get all the values for firstTime and secondTime, knowing that there could be more <record> in other XML file?

广告系列

@XmlRootElement(name = "Campaign")
@XmlType(name = "Campaign", propOrder = {
    "Name",
    "Type",
    "Record" })
public class Campaign {
    @XmlElement(required = true)
    protected Name Name;

    @XmlElement(required = true)
    protected Type Type;

    @XmlElement(required = true)
    protected List<Record> Record= new ArrayList<Record>();


    public Name getName () {return Name;}
    public void setName (Name value) {this.Name= value;}

    public Type getType () {return Type;}
    public void setType (Type value) {this.Type = value;}

    public void setRecord(Recordvalue) {this.Record.add(value);}
}

记录类

@XmlRootElement(name = "Record")
@XmlType(name = "Record", propOrder = {
    "firstTime",
    "secondTime" })
public class Record{
    @XmlElement(required = true)
    protected firstTime firstTime;

    @XmlElement(required = true)
    protected secondTime secondTime;


    public Name getFirstTime () {return firstTime;}
    public void setFirstTime (firstTime value) {this.firstTime= value;}

    public Name getSecondTime () {return secondTime;}
    public void setSecondTime (secondTime value) {this.secondTime= value;}
}

程序更大，但是不断重复..我需要提取所有内容以便以后上传到数据库. 但是现在，我只需要在屏幕上打印它们，并且知道我已经拥有了所有需要的值即可.

The program is much more big, but it just keeps repeating.. I need to extract everything in order to upload to a DB later. But now, I only need to print them on screen and knowing that I have all the values I'd need.

是的，我也查看了该链接，我不知道为什么我不能专心于如何继续，看来最糟糕的部分对我来说更容易！

Yes I had a look at that link too, I don't know why I just can't concentrate on how to continue, seems that the worst part was easier for me!

谢谢

编辑3 : 我忘了粘贴set和get的方法.

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "Type")
public class Type {

    @XmlAttribute
    protected String value;

    public String getValue() {return value;}
    public void setValue(String value) {this.value = value;}
}

所有内容都相同，我只是在此处粘贴了类型.

It is the same for all, I simply pasted Type here.

分辨率 我终于能够找到解决方案，而不是提出并标记为正确的解决方案.尽管它帮助我创建了getRecord()吸气剂.

EDIT 4: The resolution I was finally able to find the solution, which is not the one proposed and marked as correct. Although it helped me creating the getRecord() getter.

无需更改我的代码，而是添加到record.class:

Without changing my code, but adding to the record.class:

public List<Record> getRecord() { return this.Record; }

并进入主要类别:

for (int i=1; i<=campaign.getRecord().size(); i++)   {                System.out.println(campaign.getRecord().get(i-1).getFirstTime().getValue());
System.out.println(campaign.getRecord().get(i-1).getSecondTime().getValue());
}

我能够打印"13"和"14"，更一般而言，我能够打印record内的任何内容，如果record里面还有另一个列表，则另外一个:

I am able to print "13" and "14", more in general, I am able to print anything inside record and if record would have another List inside, one more:

for (int j=1; j<= campaign.getRecord().get(i-1).getANewListInsideRecord().size(); j++) {
System.out.println(campaign.getRecord().get(i-1).getANewListInsideRecord().get(j-1).getAObject().getValue());
}

将完成这项工作.

-1，因为它从0开始.

-1 because it starts from 0.

推荐答案

我仍然不确定您的问题是什么.告诉我我的答案是否不是您想要的.

I'm still unsure about what your problem is. Tell me if my answer is not what you're looking for.

您需要进行一些更改:

@XmlRootElement(name = "campaign")
@XmlType(name = "campaign", propOrder = {
    "name",
    "type",
    "record" })
public class Campaign {
    @XmlElement(required = true)
    protected Name name;

    @XmlElement(required = true)
    protected Type type;

    @XmlElement(required = true)
    protected List<Record> record;


    public Name getName () {return name;}
    public void setName (Name value) {this.name= value;}

    public Type getType () {return type;}
    public void setType (Type value) {this.type = value;}

    //Initialise your record list inside the getter instead of in member declaration
    public List<Record> getRecord() {
        if(this.record == null) record = new ArrayList<>();
        return this.record;
    }

    //Do not use a setter as an add method for the list
    public void setRecord(List<Record> value) {this.record = value;}

    //If you need to add record inside your list, do not use a setter, define an add method or access the list with the getter.
    public void addRecord(Record value) {this.record.add(value);}
}

假设您已经为Campaign中使用的所有类定义了正确的toString()方法.

I'll go under the assumption that you have defined proper toString() method for all of the classes used in the Campaign.

例如，Record类字符串可能像这样:

For exemple, the Record class string may go like :

@Override
public String toString(){
    return " First value : + "this.firstTime.getValue() + " Second value : " +this.secondTime.getValue();
}

现在显示所有内容:

List<File> files = new ArrayList<>();

//Add all XML Files containing a campaign root element into the files list
JAXBContext c = JAXBContext.newInstance(Campaign.class);
Unmarshaller u = c.createUnmarshaller();

//Declare list to store all of your camapaign object
List<Campaign> campaigns = new ArrayList<>();

for(File f : files)
{
    campaigns.add(u.unmarshall(f));
}

//display all campaigns
for(Campaign camp : campaigns){
    System.out.println(camp.getName());
    System.out.println(camp.getType());

    //Display all records
    for(Record rec : camp.getRecord()){
        System.out.println(rec);
    }
}

您当然可以将System.out.println()行更改为所需的任何代码.

You can of course change the System.out.println() lines to whatever code you want.

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