遍历Jekyll中的子类别 [英] Iterate over subcategories in Jekyll

问题描述

在Jekyll中，帖子可以具有多个类别.例如，意大利面的食谱可能具有类别dinner和food.是否可以在没有插件的情况下迭代类别(食物)的其他类别(不同的晚餐时间)?例如，我要为类别food生成以下页面:

In Jekyll, a post can have multiple categories. For example, a recipe for spaghetti might have the categories dinner and food. Is it possible--without plugins--to iterate over the other categories (different dinner times) of a category (food)? For example, I want to generate the following page for the category food:

Dinner:
* Spaguetti
* Meatloaf

Breakfast
* Cheerios
* Oatmeal

Lunch
* BLT

推荐答案

就像许多Jekyll的工作一样，答案是通过循环方式超出您的预期:)

Like a lot of Jekyll work, the answer is to loop through stuff way more than you think you should :)

只需遍历所有类别或标记或整个网站的任何内容，并使用if标记可避免输出本文中没有的内容.

Just loop through all categories or tags or whatever for your entire site, and use an if tag to avoid outputting ones that this post doesn't have.

然后在循环正文中，再次使用if标记循环浏览站点上的每个帖子，以避免输出不具有该类别的帖子.

Then inside the loop body, loop through every post on your site, using if tags again to avoid outputting the ones that don't have the category.

这里有一些代码将对标签执行此操作，我认为如果将tags替换为categories，它将起到相同的作用.我已经从我自己的网站上对其进行了轻微修改，如果有错字或两个错字，我们对此表示抱歉:

Here's some code that will do it for tags, I think if you replace tags with categories it'll work the same. I've lightly modified it from my own site, sorry if there's a typo or two:

{% for topic in site.tags | sort_by:topic order:ascending %}
    {% if topic == whatever_topic_you_have %}
        <section class="topic">
            <h1><a name="{{ topic }}">{{ topic }}</a></h1>
            {% for item in site.posts %}
                {% if item.tags contains topic %}
                    ...show your post/item here...
                {% endif %}
            {% endfor %}
        </section>
    {% endif %}
{% endfor %}

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