尝试返回XML响应时，Jersey返回500 [英] Jersey returns 500 when trying to return an XML response

问题描述

我正在尝试使用基于此文章.我想根据从URL传递的ID返回类的XML表示形式，但是，从 Advanced Rest Client Application (谷歌浏览器应用)尝试时，我得到了500个响应代码或浏览器.详细信息如下:

I'm trying to create my own RESTful WS application using Jersey 2.12 based from this article. I want to return an XML representation of a class depending on the id been passed from the url, however, I'm getting a 500 response code when trying from either Advanced Rest Client Application (google chrome app) or browser. Below are the details:

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns="http://java.sun.com/xml/ns/javaee" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-
    app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>WS_RESTful_Practice</display-name>
  <servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <!-- Register resources and providers under com.vogella.jersey.first package. -->
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>test.services</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
 </servlet>
 <servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/rest/*</url-pattern>
 </servlet-mapping>
</web-app> 

TestRestModel.java

TestRestModel.java

package test.model;

import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
public class TestRestModel{

    /**
     * 
     */
    private static final long serialVersionUID = -8391589100962515747L;
    private String name;
    private String content;

    public TestRestModel(String name, String content){
        this.name = name;
        this.content = content;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getContent() {
        return content;
    }

    public void setContent(String content) {
        this.content = content;
    }
}

TestResource.java

TestResource.java

package test.services;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;

import test.dao.TestModelDao;
import test.model.TestRestModel;

@Path("/test")
public class TestResource {

    @GET
    @Path("{id}")
    public Response getModel(@PathParam("id") String id){
        return Response.ok().entity(TestModelDao.instance.getModel().get(id)).build();
    }
}

TestModelDao.java

TestModelDao.java

package test.dao;

import java.util.HashMap;
import java.util.Map;
import test.model.TestRestModel;

public enum TestModelDao {
    instance;

    private Map<String, TestRestModel> container = new HashMap<String, TestRestModel>();

    private TestModelDao(){

        TestRestModel model = new TestRestModel("a", "this is first");
        container.put("1", model);
        model = new TestRestModel("b", "this is second");
        container.put("2", model);
        model = new TestRestModel("c", "this is third");
        container.put("3", model);
    }

    public Map<String, TestRestModel> getModel(){
        return container;
    }
}

我对Jersey和REST完全陌生.而且我还不知道如何从Jersey记录错误.

I'm totally new to Jersey and REST. And I don't know how to log error from Jersey yet.

推荐答案

当您没有为JAXB bean提供默认的no arg构造函数时，就会发生这种情况.因此，在您的情况下，您应该通过添加以下内容来修改该类:

This happens when you don't provide a default no arg constructor to your JAXB bean. So in your case you should amend the class by adding one:

  public TestRestModel(){

    }

这是由于 JSR中的要求所致-222 :

由用户创建的

现有类型必须提供一个无参数 构造函数.在编组期间，unmarshaller使用no arg构造函数 取消编组以创建该类型的实例.

existing types, authored by users, are required to provide a no arg constructor. The no arg constructor is used by an unmarshaller during unmarshalling to create an instance of the type.

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