如何删除XYLineAndShapeRenderer中的点? [英] How do I remove the points in XYLineAndShapeRenderer?

问题描述

我正在使用JFreeChart在Java中创建一个应用程序，其中显示了XY折线图.问题在于它在行上显示了数据集的每个点，而我不想显示这些点.关于如何删除这些点或使其不可见的任何想法?

I'm making an application in Java using JFreeChart which shows an XY line chart. The problem is that it shows every point of the dataset on the lines, and I don't want to display these points. Any idea on how to remove the points or make them not visible?

这是一个示例屏幕截图:

This is a sample screenshot:

这是代码:

JFrame frame = new JFrame();                
XYLineAndShapeRenderer renderer = new XYLineAndShapeRenderer();
renderer.setSeriesPaint(0, Color.RED);
renderer.setSeriesStroke(0, new BasicStroke(2.0f, 
BasicStroke.CAP_ROUND, BasicStroke.JOIN_ROUND, 1.0f,
    new float[] { 2.0f, 4.0f }, 0.0f));
XYDataset ds = createDataset(i, p, capacity);
JFreeChart xylineChart = ChartFactory.createXYLineChart("", "", 
"", ds, PlotOrientation.VERTICAL, true, true, false);
XYPlot plot = xylineChart.getXYPlot();
plot.setDomainGridlinePaint(Color.BLACK);
plot.setRangeGridlinePaint(Color.BLACK);
plot.setBackgroundPaint(Color.WHITE);
plot.setRenderer(renderer);
ChartPanel cp = new ChartPanel(xylineChart);
frame.getContentPane().add(cp);

推荐答案

默认情况下，无参数构造器 /chart/renderer/xy/XYLineAndShapeRenderer.html"rel =" nofollow noreferrer> XYLineAndShapeRenderer 创建同时可见线和形状的新渲染器.要删除这些点，您可以

By default, the no-argument constructor of XYLineAndShapeRenderer "Creates a new renderer with both lines and shapes visible." To remove the points, you can

• 使用替代构造函数以指定所需的组合-没有形状的线，如此处所示并在 :

• Use the alternative constructor to specify the desired combination—lines without shapes, as shown here and in ChartFactory.createXYLineChart:

XYLineAndShapeRenderer renderer = new XYLineAndShapeRenderer(true, false);

调用setSeriesShapesVisible()，因为@abhinavxeon建议此处和作者建议

Invoke setSeriesShapesVisible(), as @abhinavxeon suggests here and the author suggests here:

renderer.setSeriesShapesVisible(0, false)

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