JOOQ sbt从0.3.16迁移到1.2.8 [英] JOOQ sbt 0.3.16 to 1.2.8 migration

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本文介绍了JOOQ sbt从0.3.16迁移到1.2.8的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何将JOOQ构建和配置从sbt 0.3.16迁移到sbt 1.2.8

How migrate JOOQ building and configuration from sbt 0.3.16 to sbt 1.2.8

0.3.16中的JOOQ构建定义如下.

The JOOQ build definition in 0.3.16 as below.

val generateJOOQ = taskKey[Seq[File]]("Generate JooQ classes")

val generateJOOQTask = (baseDirectory, dependencyClasspath in Compile, runner in Compile, streams) map { (base, cp, r, s) =>
  toError (r.run(
    "org.jooq.util.GenerationTool",
    cp.files,
    Array("conf/openDoor.xml"),
    s.log))
  ((base / "app" / "jooqSteps") ** "*.scala").get
}

generateJOOQ <<= generateJOOQTask

以及运行sbt(1.2.8)时的结果:

and the result when running sbt (1.2.8):

build.sbt:70: error: value map is not a member of (sbt.SettingKey[java.io.File], sbt.TaskKey[sbt.Keys.Classpath], sbt.TaskKey[sbt.ScalaRun], sbt.TaskKey[sbt.Keys
.TaskStreams])
val generateJOOQTask = (baseDirectory, dependencyClasspath in Compile, runner in Compile, streams) map { (base, cp, r, s) =>
                                                                                                   ^
C:\workPlay\anchor\build.sbt:71: error: not found: value toError
  toError (r.run(
  ^
[error] sbt.compiler.EvalException: Type error in expression

谢谢您的帮助

推荐答案

根据从元组扩展中迁移指南和

According to migrating from tuple enrichments guide and dropped deprecations release notes we could migrate generateJOOQTask as follows

val generateJOOQ = taskKey[Seq[File]]("Generate JooQ classes")
generateJOOQ := {
  val base = baseDirectory.value
  val cp = (dependencyClasspath in Compile).value
  val r = (runner in Compile).value
  val s = streams.value

  r.run(
    "org.jooq.util.GenerationTool",
    cp.files,
    Array("conf/openDoor.xml"),
    s.log
  ).failed foreach (sys error _.getMessage)

  ((base / "app" / "jooqSteps") ** "*.scala").get

}

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