Spring-如何从对象列表中删除属性? [英] Spring- How to remove a property from a list of Objects?

问题描述

我有一个具有以下属性的人"实体，

I have an Entity "Person" which has following properties,

Id
Name
F-Name
Age
Address

当我在Person上调用存储库函数findAll()时，它将返回一个Persons列表.

When I call a repository function findAll() on Person, it returns a list of Persons.

List<Person> list = somefuntionToConvertIterableToList(personRepository.findAll());

此列表包含多个人员类型"对象.

this list has multiple objects of Person Type.

人员...... ... Id1，Name1，F-Name1，Age1，Address1

Person ...... Id1,Name1, F-Name1, Age1, Address1

人员....... IdN，NameN，F-NameN，AgeN，地址N

Person .......IdN,NameN, F-NameN, AgeN, AddressN

我需要从所有人中删除"Id"，我该怎么办?

I need to remove "Id" from all Persons, what should I do?

我知道我们可以使用删除"来删除列表中的元素，但是如何删除元素中的属性?

I know we can use "remove" to delete an element of list, but how to delete a property with in an element?

推荐答案

我认为您需要使用:@JsonIgnore in Id如下:

I think you need used : @JsonIgnore in Id look like:

@JsonIgnore
   Field you want remove in reponse.

或者您可以创建DTO，然后将要返回的所有字段都显示为:

Or you can create DTO and put all field you want return look like :

  public class PersonDTO {
      //all field you want return
   }

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