使用jQuery UI Datepicker确保日期至少比另一个日期晚1天 [英] Ensuring a date is at least 1 day later than another date using jQuery UI Datepicker

问题描述

使用jQuery DatePicker，我想确保离开日期至少是到达日期之后的1天.我设法做到的最接近的方法是确保出发日期与到达日期在同一天(我只是不知道如何在JS中添加"selectedDate + 1天").谢谢您的帮助.

这是我的JS:

$(".datepicker_arrival").datepicker({
  dateFormat: 'dd/mm/yy',
  minDate: new Date(),
  onSelect: function(dateText, inst) {
    if($('.datepicker_departure').val() == '') {
      var current_date = $.datepicker.parseDate('dd/mm/yy', dateText);
      current_date.setDate(current_date.getDate()+1);
      $('.datepicker_departure').datepicker('setDate', current_date);
    }
  },
  onClose: function( selectedDate ) {
    $( ".datepicker_departure" ).datepicker( "option", "minDate", selectedDate );
  }
});

$(".datepicker_departure").datepicker({
  dateFormat: 'dd/mm/yy',
  minDate: new Date(),
  onClose: function( selectedDate ) {
    $( ".datepicker_arrival" ).datepicker( "option", "maxDate", selectedDate );
  }
});

这是我的HTML:

<input type="text" name="arrival" class="datepicker datepicker_arrival textfield" placeholder="Arrival Date" />

<input type="text" name="departure" class="datepicker datepicker_departure textfield" placeholder="Departure Date" />

解决方案

您可以在onClose方法中传递datepicker对象:

http://api.jqueryui.com/datepicker/#option- onClose

因此，这应该可以正常工作:

$(".datepicker_arrival").datepicker({
  dateFormat: 'dd/mm/yy',
  minDate: new Date(),
  onSelect: function(dateText, inst) {
    if($('.datepicker_departure').val() == '') {
      var current_date = $.datepicker.parseDate('dd/mm/yy', dateText);
      current_date.setDate(current_date.getDate()+1);
      $('.datepicker_departure').datepicker('setDate', current_date);
    }
  },
  onClose: function( selectedDate, test) {
     var  MyDateString = ('0' + (parseInt(test.selectedDay)+1)).slice(-2) + '/'
             + ('0' + (test.selectedMonth+1)).slice(-2) + '/'
             + test.selectedYear;
      $( ".datepicker_departure" ).datepicker( "option", "minDate", MyDateString);
  }
});

提琴:

http://jsfiddle.net/SpAm/9mSxk/1/

填充想法的信用来自于user113716在此线程中接受的答案:

Javascript向日期添加前导零

Using jQuery DatePicker, I'd like to ensure that the departure date is at least 1 day after the arrival date. The closest I've managed to get to this is to ensure that the departure date is on the same day as the arrival date (I just couldn't figure out how to add 'selectedDate + 1 day' in the JS). I'd appreciate any help with this, thanks.

Here's my JS:

$(".datepicker_arrival").datepicker({
  dateFormat: 'dd/mm/yy',
  minDate: new Date(),
  onSelect: function(dateText, inst) {
    if($('.datepicker_departure').val() == '') {
      var current_date = $.datepicker.parseDate('dd/mm/yy', dateText);
      current_date.setDate(current_date.getDate()+1);
      $('.datepicker_departure').datepicker('setDate', current_date);
    }
  },
  onClose: function( selectedDate ) {
    $( ".datepicker_departure" ).datepicker( "option", "minDate", selectedDate );
  }
});

$(".datepicker_departure").datepicker({
  dateFormat: 'dd/mm/yy',
  minDate: new Date(),
  onClose: function( selectedDate ) {
    $( ".datepicker_arrival" ).datepicker( "option", "maxDate", selectedDate );
  }
});

Here's my HTML:

<input type="text" name="arrival" class="datepicker datepicker_arrival textfield" placeholder="Arrival Date" />

<input type="text" name="departure" class="datepicker datepicker_departure textfield" placeholder="Departure Date" />

解决方案

You can pass the datepicker object in the onClose method:

http://api.jqueryui.com/datepicker/#option-onClose

Consequently, this should work fine:

$(".datepicker_arrival").datepicker({
  dateFormat: 'dd/mm/yy',
  minDate: new Date(),
  onSelect: function(dateText, inst) {
    if($('.datepicker_departure').val() == '') {
      var current_date = $.datepicker.parseDate('dd/mm/yy', dateText);
      current_date.setDate(current_date.getDate()+1);
      $('.datepicker_departure').datepicker('setDate', current_date);
    }
  },
  onClose: function( selectedDate, test) {
     var  MyDateString = ('0' + (parseInt(test.selectedDay)+1)).slice(-2) + '/'
             + ('0' + (test.selectedMonth+1)).slice(-2) + '/'
             + test.selectedYear;
      $( ".datepicker_departure" ).datepicker( "option", "minDate", MyDateString);
  }
});

Fiddle:

http://jsfiddle.net/SpAm/9mSxk/1/

Credit for the padding idea comes from the accepted answer by user113716 in this thread:

Javascript add leading zeroes to date

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