在j_security_check JSF 2.0中获取j_username [英] get j_username in j_security_check JSF 2.0

问题描述

我有一个简单的页面，我想检索j_username以将其保存为会话中的登录用户，我无法从表单中获取它.服务器在此代码中自行执行身份验证

I have simple page, I want to retrieve j_username to save it in session as a logged in user, i can't fetch it from the form. here Server it self perform authentication in this code

<h:form id="login" onsubmit="document.getElementById('login').action='j_security_check';" prependId="false">
                <h:panelGrid columns="2">
                    <p:outputLabel for="j_username" value="Username" />
                    <p:inputText id="j_username" name="j_username"/>            
                    <p:outputLabel for="j_password" value="Password" />
                    <p:password id="j_password" name="j_password" value=""/>
                    <p:commandButton style="font-size:15px" type="submit"  value="Login" ajax="false"/>
                    <p:commandButton style="font-size:15px" type="clear" value="Clear" ajax="false"/>
                </h:panelGrid>
            </h:form>

推荐答案

因此，这应该在视图中执行:

So, this should do either in the view:

<ui:fragment rendered="#{empty request.remoteUser}">
    <p>This is only rendered when someone's NOT logged in.</p>
</ui:fragment>
<ui:fragment rendered="#{not empty request.remoteUser}">
    <p>This is only rendered when someone's been logged in.</p>
    <p>Welcome, you're logged in as #{request.remoteUser}!</p>
</ui:fragment>

或在托管bean中:

ExternalContext ec = FacesContext.getCurrentInstance().getExternalContext();
String username = ec.getRemoteUser();
// ...

---

无关:与具体问题无关:最好摆脱这种onsubmit废话，而只需使用普通的<form>而不是<h:form>.

---

Unrelated to the concrete problem: it's better to get rid of that onsubmit nonsense and just use plain <form> instead of <h:form>.

<form id="login" action="j_security_check">

这样，它也可以在禁用JS的客户端上使用.

This way it'll also work on JS-disabled clients.

• 执行使用j_security_check
在Java EE/JSF中进行用户身份验证

• Performing user authentication in Java EE / JSF using j_security_check

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