JSON.parse:JSON数据后出现意外的非空白字符 [英] JSON.parse: unexpected non-whitespace character after JSON data

问题描述

我正在尝试使用json对象从数据库中检索数据.但是当我调用servlet时，Jquery将返回SyntaxError: JSON.parse: unexpected non-whitespace character after JSON data.此错误仅在响应包含更多数据时显示.

I'm trying to retrieve the data from the database using the json object. But when i call the servlet, the Jquery will returns SyntaxError: JSON.parse: unexpected non-whitespace character after JSON data This error only shows when the response contains more data.

我的脚本是:

    $.ajax({
       type: "GET",
        url: "VComment",
        data:'comm='+encodeURIComponent(comm)+'&'+'data-id='+encodeURIComponent(dataid)+'&'+'data-alid='+encodeURIComponent(dataalid),
        dataType: "json",
        success: function( data, textStatus, jqXHR) 
        {
            if(data.success)
            {
                    var newcommhtml = '<div id="c0'+thecid+'" class="cnew clearfix"> <section class="c-author">';
                    newcommhtml = newcommhtml + '<h3>Anonymous</h3>';
                    newcommhtml = newcommhtml + '<span class="pubdate">'+month+' '+day+', '+year+'</span> </section>';
                    newcommhtml = newcommhtml + '<section class="c-content">';
                    newcommhtml = newcommhtml + '<img src="images/green-avatar.png" alt="avatar" width="80" height="80" class="ava">';
                    newcommhtml = newcommhtml + '<p>'+nl2br(data.commentInfo.comment)+'</p> </section></div>';

                    var thelm = "#c0"+thecid;
                    commwrap.append(newcommhtml);
                    $(thelm).hide().fadeIn('slow');

                    setTimeout(function() { $(thelm).addClass('green'); }, 800);

                    $("#comm").val("");
                    thecid++;

                    if(errorspan.html() != null) {
                        errorspan.remove();
                    }
            }

          },
     error: function(jqXHR, textStatus, errorThrown)
      {
         alert("error"+errorThrown);
         console.log("Something really bad happened " + textStatus);
      },
});

并且收到了回复.

    {"success":true,"commentInfo":{"uname":"shyam","comment":"rreter","itemId":0}}
    {"success":true,"commentInfo":{"uname":"shyam","comment":"dfdsfdd","itemId":0}}
    {"success":true,"commentInfo":{"uname":"shyam","comment":"xzdfdsfdd","itemId":0}}
    {"success":true,"commentInfo":{"uname":"shyam","comment":"sdfsd fsdfs","itemId":0}}
    {"success":true,"commentInfo":{"uname":"shyam","comment":"sdsd","itemId":0}}
    {"success":true,"commentInfo":{"uname":"shyam","comment":"dd","itemId":0}}
    {"success":true,"commentInfo":{"uname":"shyam","comment":"dddf","itemId":0}}

Servlet代码:

Servlet code :

      while(rs.next()){
            Commenter comment = new Commenter();
            comment.setUname(rs.getString("uname").trim());
            comment.setComment(rs.getString("comments").trim());
            commentObj=gson.toJsonTree(comment);
            myObj.add("commentInfo", commentObj);
            out.println(myObj.toString());
            }   

请任何人告诉我如何解决此问题...谢谢....

Please anyone tell me how to solve this problem ... Thanks....

推荐答案

尝试此代码，我认为它可以解决您的问题:

try this code I think It may solve Your problem :

        ArrayList<JSONObject> CommArray=new ArrayList<JSONObject>();

         while(rs.next()){
            JSONObject Obj = new JSONObject();
            Obj.put("uname",rs.getString("uname").trim());     //Adds your uname to Object
            Obj.put("comment",rs.getString("comments").trim());//Adds your comment to Object
            CommArray.add(Obj);                                //Inserts your Object to ArrayList
            System.out.println(rs.getString("comments").trim());
            }    
         JSONArray arrayObj=JSONArray.fromObject(CommArray);//Converts the Array List to JSONArray
         commentObj=gson.toJsonTree(arrayObj);   //Converts the JSONArray to Jsontree
         myObj.add("commentInfo", commentObj);   //Adds the Tree to JsonObject as commentInfo Array
         out.println(myObj.toString());        //Prints the result
         rs.close();                                                              
         stmt.close();                                                            
         stmt = null;                                                             
         conn.close();                                                            
         conn = null;                                                  

     }                                                              
     catch(Exception e){}

我希望这可以解决您的问题.

I hope this solves Your problem.

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