如何通过jQuery中的请求主体提交JSON数据? [英] How to submit JSON Data by Request Body in jQuery?
本文介绍了如何通过jQuery中的请求主体提交JSON数据?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我不是jQuery专家,请考虑一下我.这是我的代码,它不负责由请求正文提交jQuery JSON数据.
I am not expert in jQuery, consider me fresher. Here is my code which one not responsible for jQuery JSON data submission by Request Body.
<!doctype html>
<html lang="en">
<head>
<title>jQuery Data submitted by JSON Body Request</title>
<script type="text/javascript" src="jquery-1.3.2.js"></script>
<script type="text/javascript">
$.ajax({
url : "/",
type: "POST",
data: [
{id: 1, name: "Shahed"},
{id: 2, name: "Hossain"}
],
contentType: "application/json; charset=utf-8",
dataType : "json",
success : function(){
console.log("Pure jQuery Pure JS object");
}
});
</script>
</head>
<body>
<p>
Example of submission JS Object by JSON Body Request<br/>
Its could submitted mass amount of data by Message body<br/>
It's secured and faster than any data submission .
</p>
</body>
</html>
帖子来源出现了
Shahed=undefined&Hossain=undefined
但所需的帖子来源是:
[{"id":1,"name":"Shahed"},{"id":2,"name":"Hossain"}]
如何为每个请求正文获取所需的帖子来源?
How do I get the desired Post Source for each Request Body?
推荐答案
以下是适合您所需输出的正确代码.
Here is the right code for your desired out put.
$.ajax({
url : "/",
type: "POST",
data: JSON.stringify([
{id: 1, name: "Shahed"},
{id: 2, name: "Hossain"}
]),
contentType: "application/json; charset=utf-8",
dataType : "json",
success : function(){
console.log("Pure jQuery Pure JS object");
}
});
您必须将JS Object转换为String,并且JSON.stringify(JSObject)
是负责此操作的方法.
Your must convert JS Object to String and JSON.stringify(JSObject)
is the method responsible for that.
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