Golang-通过更改键值取消编组JSON [英] Golang - Unmarshall JSON with changing key value
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问题描述
我正在尝试将JSON解组到结构中,但是事实证明这很困难,因为外部JSON密钥发生了变化,而我才在一周前才开始使用.这是我的手动尝试:
I'm trying to unmarshall JSON into a struct, but it's proving difficult because the outer JSON key changes and I only started go a week ago. This is my manual attempt:
import (
"encoding/json"
"fmt"
"strconv"
)
type Device struct {
localUUID string
applicationUUID string
externalUUID string
commit string
lastSeen string
state string
progress float32
}
func main() {
devices := make([]*Device, 0, 10)
b := []byte(`{
"5417871461137421886": {
"applicationUUID": "test_applicationUUID",
"commit": "test_commit",
"lastSeen": "test_lastSeen",
"localUUID": "E4:F5:13:8E:F5:43",
"progress": "3.5",
"externalUUID": "test_externalUUID",
"state": "test_state"
},
"5632882567440442530": {
"applicationUUID": "test_applicationUUID",
"commit": "test_commit",
"lastSeen": "test_lastSeen",
"localUUID": "E4:F5:13:8E:F5:42",
"progress": "3.5",
"externalUUID": "test_externalUUID",
"state": "test_state"
},
"8912255216147730520": {
"applicationUUID": "test_applicationUUID",
"commit": "test_commit",
"lastSeen": "test_lastSeen",
"localUUID": "E4:F5:13:8E:F5:41",
"progress": "3.5",
"externalUUID": "test_externalUUID",
"state": "test_state"
}
}`)
var f interface{}
json.Unmarshal(b, &f)
outer := f.(map[string]interface{})
for _, value := range outer {
inner := value.(map[string]interface{})
device := &Device{}
device.localUUID = inner["localUUID"].(string)
device.applicationUUID = inner["applicationUUID"].(string)
device.externalUUID = inner["externalUUID"].(string)
device.commit = inner["commit"].(string)
device.lastSeen = inner["lastSeen"].(string)
device.state = inner["state"].(string)
f, _ := strconv.ParseFloat(inner["progress"].(string), 32)
device.progress = float32(f)
devices = append(devices, device)
}
for _, device := range devices {
fmt.Println(device)
}
}
是否有一种方法可以忽略键并遍历值,从而允许我使用json.Unmarshal(b,& Device)?
Is there a way to ignore the keys and iterate over the values instead, allowing me to use json.Unmarshal(b, &Device)?
推荐答案
您有一系列JSON对象,映射是每个Device
的唯一ID.将其解组为map
You have a series of JSON objects, mapping a unique id to each Device
. Unmarshal that into a map
type Device struct {
LocalUUID string `json:"localUUID"`
ApplicationUUID string `json:"applicationUUID"`
ExternalUUID string `json:"externalUUID"`
Commit string `json:"commit"`
LastSeen string `json:"lastSeen"`
State string `json:"state"`
Progress float32 `json:"progress,string"`
}
func main() {
devices := make(map[string]*Device)
err := json.Unmarshal(b, &devices)
if err != nil {
log.Fatal(err)
}
for _, device := range devices {
fmt.Printf("%#v\n", device)
}
}
https://play.golang.org/p/JDZzG64jJR
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