在不知道键的情况下解析json [英] Parse json without knowning the keys

问题描述

我试图在不知道键和json格式的结构的情况下用java解析json并将该数据保存到哈希图中

i am trying to parse json in java without knowing the keys and the structure of json format and save that data into the hashmap

我将如何循环遍历整个json格式并将键和值存储到哈希图中

how would i cycle through the whole json format and store key and value into the hashmap

 {"id" : 12345, "value" : "123", "person" : "1"}

像本例一样，所有键都是jsonobject，它们都不是json数组

like in this example all the keys would be jsonobject none of them will be json array

还有其他一些库，例如杰克逊，我不想使用任何第三方库

There is some other library like jackson i don't want to use any third party library

推荐答案

这只是一个示例. 对于像

This is Just an Example. For a JSON Like

{
 "status": "OK",
 "search_result": [

            {
                "product": "abc",
                "id": "1132",
                "question_mark": {
                    "141": {
                        "count": "141",
                        "more_description": "this is abc",
                        "seq": "2"
                    },
                    "8911": {
                        "count": "8911",
                        "more_desc": "this is cup",
                        "seq": "1"
                    }
                },
                "name": "some name",
                "description": "This is some product"
            },
            {
                "product": "XYZ",
                "id": "1129",
                "question_mark": {
                    "379": {
                        "count": "379",
                        "more_desc": "this is xyz",
                        "seq": "5"
                    },
                    "845": {
                        "count": "845",
                        "more_desc": "this is table",
                        "seq": "6"
                    },
                    "12383": {
                        "count": "12383",
                        "more_desc": "Jumbo",
                        "seq": "4"
                    },
                    "257258": {
                        "count": "257258",
                        "more_desc": "large",
                        "seq": "1"
                    }
                },
                "name": "some other name",
                "description": "this is some other product"
            }
       ]
}

使用JSONObject keys()获取密钥，然后迭代每个密钥以获取动态值.

Use JSONObject keys() to get the key and then iterate each key to get to the dynamic value.

大致代码如下:

// searchResult refers to the current element in the array "search_result"
JSONObject questionMark = searchResult.getJSONObject("question_mark");
Iterator keys = questionMark.keys();

while(keys.hasNext()) {
    // loop to get the dynamic key
    String currentDynamicKey = (String)keys.next();

    // get the value of the dynamic key
    JSONObject currentDynamicValue = questionMark.getJSONObject(currentDynamicKey);

    // do something here with the value...
}

也可以尝试使用此代码

public void parse(String json)  {
   JsonFactory factory = new JsonFactory();

   ObjectMapper mapper = new ObjectMapper(factory);
   JsonNode rootNode = mapper.readTree(json);  

   Iterator<Map.Entry<String,JsonNode>> fieldsIterator = rootNode.fields();
   while (fieldsIterator.hasNext()) {

       Map.Entry<String,JsonNode> field = fieldsIterator.next();
       System.out.println("Key:"field.getKey() + "\tValue:" + field.getValue());
   }

}

也请看一下此链接

https://github.com/alibaba/fastjson

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