如何使用python扁平化JSON数组? [英] How to flatten a JSON array with python?

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问题描述

我正在处理JSON结构,其输出如下:

I'm dealing with a JSON structure, which is output as follows:

{
    "time": "2015-10-20T20:15:00.847Z",
    "name": "meta.response.ean",
    "level": "info",
    "data1": {
        "HotelListResponse": {
            "customerSessionId": "0AB29024-F6D4-3915-0862-DB3FD1904C5A",
            "numberOfRoomsRequested": 1,
            "moreResultsAvailable": true,
            "cacheKey": "-705f6d43:15086db3fd1:-4c58",
            "cacheLocation": "10.178.144.36:7300",
            "HotelList": {
                "@size": 2,
                "@activePropertyCount": 2,
                "HotelSummary": [{
                        "hotelId": 132684,
                        "city": "Seattle",
                        "highRate": 159.0,
                        "lowRate": 159.0,
                        "rateCurrencyCode": "USD",
                        "RoomRateDetailsList": {
                            "RoomRateDetails": {
                                "roomTypeCode": 10351,
                                "rateCode": 10351,
                                "roomDescription": "Standard Room, 1 Queen Bed",
                                "RateInfos": {
                                    "RateInfo": {
                                        "@promo": false,
                                        "ChargeableRateInfo": {
                                            "@averageBaseRate": 159.0,
                                            "@averageRate": 159.0,
                                            "@currencyCode": "USD",
                                            "@nightlyRateTotal": 159.0,
                                            "@surchargeTotal": 26.81,
                                            "@total": 185.81
                                        }
                                    }
                                }
                            }
                        }
                    }, {
                        "hotelId": 263664,
                        "city": "Las Vegas",
                        "highRate": 135.0,
                        "lowRate": 94.5,
                        "rateCurrencyCode": "USD",
                        "RoomRateDetailsList": {
                            "RoomRateDetails": {
                                "roomTypeCode": 373685,
                                "rateCode": 1238953,
                                "roomDescription": "Standard Room, 1 King Bed",
                                "RateInfos": {
                                    "RateInfo": {
                                        "@promo": true,
                                        "ChargeableRateInfo": {
                                            "@averageBaseRate": 135.0,
                                            "@averageRate": 94.5,
                                            "@currencyCode": "USD",
                                            "@nightlyRateTotal": 94.5,
                                            "@surchargeTotal": 9.45,
                                            "@total": 103.95
                                        }
                                    }
                                }
                            }
                        }
                    }
                ]
            }
        }
    },
    "context": {
        "X-Request-Id": "dca47992-b6cc-4b87-956c-90523c0bf3bb",
        "host": "getaways-search-app2",
        "thread": "http-nio-80-exec-12"
    }
}

如您所见,这些是嵌套数组.关于递归地展平它们有很多讨论.我无法展平HotelSummary下的数组.有什么想法吗?

As you can see, these are nested arrays. There is much discussion about flattening these recursively. I am unable to flatten the arrays under HotelSummary. Any ideas?

  • 我想将JSON的一部分拼合为以下形式:
{  
   "customerSessionId":"0AB29024-F6D4-3915-0862-DB3FD1904C5A",
   "numberOfRoomsRequested":1,
   "moreResultsAvailable":"true",
   "cacheKey":"-705f6d43:15086db3fd1:-4c58",
   "cacheLocation":"10.178.144.36:7300",
   "size":2,
   "activePropertyCount":2,
   "hotelId":132684,
   "city":"Seattle",
   "highRate":159.0,
   "lowRate":159.0,
   "rateCurrencyCode":"USD",
   "roomTypeCode":10351,
   "rateCode":10351,
   "roomDescription":"Standard Room, 1 Queen Bed",
   "promo":"false",
   "averageBaseRate":159.0,
   "averageRate":159.0,
   "currencyCode":"USD",
   "nightlyRateTotal":159.0,
   "surchargeTotal":26.81,
   "total":185.81
}


{  
   "customerSessionId":"0AB29024-F6D4-3915-0862-DB3FD1904C5A",
   "numberOfRoomsRequested":1,
   "moreResultsAvailable":"true",
   "cacheKey":"-705f6d43:15086db3fd1:-4c58",
   "cacheLocation":"10.178.144.36:7300",
   "size":2,
   "activePropertyCount":2,
   "hotelId":263664,
   "city":"Las Vegas",
   "highRate":135.0,
   "lowRate":94.5,
   "rateCurrencyCode":"USD",
   "roomTypeCode":373685,
   "rateCode":1238953,
   "roomDescription":"Standard Room, 1 King Bed",
   "promo":"true",
   "averageBaseRate":135.0,
   "averageRate":94.5,
   "currencyCode":"USD",
   "nightlyRateTotal":94.5,
   "surchargeTotal":9.45,
   "total":103.95
}

  • 我尝试使用flattenDict类.我没有得到所需格式的输出.
    • I have tried using flattenDict class. I am not getting the output in the desired format.
    • def flattenDict(d, result=None):
          if result is None:
              result = {}
          for key in d:
              value = d[key]
              if isinstance(value, dict):
                  value1 = {}
                  for keyIn in value:
                      value1[".".join([key,keyIn])]=value[keyIn]
                  flattenDict(value1, result)
              elif isinstance(value, (list, tuple)):   
                  for indexB, element in enumerate(value):
                      if isinstance(element, dict):
                          value1 = {}
                          index = 0
                          for keyIn in element:
                              newkey = ".".join([key,keyIn])        
                              value1[".".join([key,keyIn])]=value[indexB][keyIn]
                              index += 1
                          for keyA in value1:
                              flattenDict(value1, result)   
              else:
                  result[key]=value
          return result
      

      推荐答案

      使用 pandas & json_normalize :

      • record_path是主要key要展平的参数
      • meta是用于附加keys进行展平的参数
      • json_normalize创建的列名包括所有keys到所需的key,因此长列名(例如RoomRateDetailsList.RoomRateDetails.roomTypeCode)
      • 长列名称需要重命名为较短的版本
      • dict理解用于创建rename dict.
      • 以下代码利用了 pathlib
      • .openpathlib
      • 的方法
      • 也适用于非Windows路径
      • Use pandas & json_normalize:

        • record_path is the parameter for the main key to flatten
        • meta is the parameter for additional keys to flatten
        • json_normalize creates column names that include all keys to the desired key, hence the long column names (e.g. RoomRateDetailsList.RoomRateDetails.roomTypeCode)
        • Long column names need to be renamed to shorter versions
        • A dict comprehension is used to create a rename dict.
        • The following code takes advantage of the pathlib library
        • .open is a method of pathlib
        • Works with non-Windows paths too
        • import pandas as pd
          import json
          from pathlib import Path
          
          
          # path to file
          p = Path(r'c:\some_path_to_file\test.json')
          
          # read json file
          with p.open('r', encoding='utf-8') as f:
              data = json.loads(f.read())
          
          # create dataframe
          df = pd.json_normalize(data,
                              record_path=['data1', 'HotelListResponse', 'HotelList', 'HotelSummary'],
                              meta=[['data1', 'HotelListResponse', 'customerSessionId'],
                                    ['data1', 'HotelListResponse', 'numberOfRoomsRequested'],
                                    ['data1', 'HotelListResponse', 'moreResultsAvailable'],
                                    ['data1', 'HotelListResponse', 'cacheKey'],
                                    ['data1', 'HotelListResponse', 'cacheLocation'],
                                    ['data1', 'HotelListResponse', 'HotelList', '@size'],
                                    ['data1', 'HotelListResponse', 'HotelList', '@activePropertyCount']])
          
          # rename columns:
          rename = {value: value.split('.')[-1].replace('@', '') for value in df.columns}
          df.rename(columns=rename, inplace=True)
          
          # dataframe view
           hotelId       city  highRate  lowRate rateCurrencyCode  roomTypeCode  rateCode             roomDescription  promo  averageBaseRate  averageRate currencyCode  nightlyRateTotal  surchargeTotal   total                     customerSessionId numberOfRoomsRequested moreResultsAvailable                     cacheKey       cacheLocation size activePropertyCount
            132684    Seattle     159.0    159.0              USD         10351     10351  Standard Room, 1 Queen Bed  False            159.0        159.0          USD             159.0           26.81  185.81  0AB29024-F6D4-3915-0862-DB3FD1904C5A                      1                 True  -705f6d43:15086db3fd1:-4c58  10.178.144.36:7300    2                   2
            263664  Las Vegas     135.0     94.5              USD        373685   1238953   Standard Room, 1 King Bed   True            135.0         94.5          USD              94.5            9.45  103.95  0AB29024-F6D4-3915-0862-DB3FD1904C5A                      1                 True  -705f6d43:15086db3fd1:-4c58  10.178.144.36:7300    2                   2
          
          # save to JSON
          df.to_json('out.json', orient='records')
          

          最终JSON输出:

          [{
                  "hotelId": 132684,
                  "city": "Seattle",
                  "highRate": 159.0,
                  "lowRate": 159.0,
                  "rateCurrencyCode": "USD",
                  "roomTypeCode": 10351,
                  "rateCode": 10351,
                  "roomDescription": "Standard Room, 1 Queen Bed",
                  "promo": false,
                  "averageBaseRate": 159.0,
                  "averageRate": 159.0,
                  "currencyCode": "USD",
                  "nightlyRateTotal": 159.0,
                  "surchargeTotal": 26.81,
                  "total": 185.81,
                  "customerSessionId": "0AB29024-F6D4-3915-0862-DB3FD1904C5A",
                  "numberOfRoomsRequested": 1,
                  "moreResultsAvailable": true,
                  "cacheKey": "-705f6d43:15086db3fd1:-4c58",
                  "cacheLocation": "10.178.144.36:7300",
                  "size": 2,
                  "activePropertyCount": 2
              }, {
                  "hotelId": 263664,
                  "city": "Las Vegas",
                  "highRate": 135.0,
                  "lowRate": 94.5,
                  "rateCurrencyCode": "USD",
                  "roomTypeCode": 373685,
                  "rateCode": 1238953,
                  "roomDescription": "Standard Room, 1 King Bed",
                  "promo": true,
                  "averageBaseRate": 135.0,
                  "averageRate": 94.5,
                  "currencyCode": "USD",
                  "nightlyRateTotal": 94.5,
                  "surchargeTotal": 9.45,
                  "total": 103.95,
                  "customerSessionId": "0AB29024-F6D4-3915-0862-DB3FD1904C5A",
                  "numberOfRoomsRequested": 1,
                  "moreResultsAvailable": true,
                  "cacheKey": "-705f6d43:15086db3fd1:-4c58",
                  "cacheLocation": "10.178.144.36:7300",
                  "size": 2,
                  "activePropertyCount": 2
              }
          ]
          

          这篇关于如何使用python扁平化JSON数组?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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