用C#创建json字符串 [英] json string creation with c#

问题描述

我正在创建一个字符串变量，用于在调用后的调用中，但是失败了.当我调试并查看json值时，我被告知它不是json格式.肯定是关键:值对，所以我不确定这里的问题是什么?

I am creating a string variable to use in an rest post call and it is failing. when I debug and look at the json value I am told it is not in json format. It sure seems to be key:value pairs so I an not sure what the issue here is?

我也尝试使用\来转义而不是双单引号(看起来这两种方法都不是好方法):

instead of double single quotes I also tried escaping the " by using \ like so (neither method is good it seems):

//string postData = "{\"title\":\"Change Title\",  \"description\":\"Create description\",  \"scheduledStartDate\": \"2018-12-24T11:24:48.91Z\",  \"scheduledEndDate'': ''2018-12-25T11:24:48.91Z''  }";

    string postData = @"{''changeNumberForClone'': ''C03688051'',
                        ''scheduledStartDate'': ''2017-12-24T11:24:48.91Z'',
                        ''scheduledEndDate'': ''2017-12-25T11:24:48.91Z''}";        

推荐答案

使用 NewtonSoft Json.NET ，您可以使用以下代码获取正确的json字符串:

Using NewtonSoft Json.NET, you could use the following code to obtain a correct json string:

Dictionary<String, String> jsonDict = new Dictionary<String, String>();
jsonDict.Add("changeNumberForClone", "C03688051");
jsonDict.Add("scheduledStartDate", "2017-12-24T11:24:48.91Z");
jsonDict.Add("scheduledEndDate", "2017-12-25T11:24:48.91Z");

String postData = JsonConvert.SerializeObject(jsonDict);

如果您不想向您的项目添加新库:

If you don't want to add a new library to your project:

String postData = "{\"changeNumberForClone\":\"C03688051\", \"scheduledStartDate\":\"2017-12-24T11:24:48.91Z\", \"scheduledEndDate\": \"2017-12-25T11:24:48.91Z\"}";

为了使用相同的方法生成具有多个深度级别的json字符串，可以按以下方式使用anonymous objects:

In order to produce json strings with multiple levels of depth using the same approach, you can use anonymous objects as follows:

var obj = new { abc = new { def = new { one="1", two="2" } } };
var json = JsonConvert.SerializeObject(obj);

，或者，如果您更喜欢使用Dictionary实例:

or, if you prefer to use Dictionary instances:

var obj = new Dictionary<String,Object>()
{
    {
        "abc", new Dictionary<String,Object>()
        {
            {
                "def" , new Dictionary<String,Object>()
                {
                    { "one", "1" }, {"two", "2" }
                }
            }
        }
    }
};

两种方法的输出如下:

{
   "abc": {
      "def" : {
         "one": "1",
         "two": "2",
      },
   }
}

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