如果是，则键拆分JSON [英] If else key split JSON

问题描述

我具有此功能:

let input = {
  "Apples": {
    "Apples": 501.82,
    "Apples_pos2": 502.61,
    "Apples_pos3": 502.61,
    "Apples": 502.16,
  }
};

let output = Object.keys(input).reduce((acc, outerKey) => {
  for (let [key, value] of Object.entries(input[outerKey])) {
    acc.push([outerKey, value, key.split('_')[1]]);
  }
  return acc;
}, []);

console.log(output);

我需要编辑它的帮助.我想要的是，如果键包含"_pos"，则执行key.split，如果键不包含"_pos"，则保持原样.

I need help editing it. What I want is if the key contains "_pos" then do key.split, if the key doesn't contain "_pos" leave it how it is.

我想要的输出是

[
 ["Apples", 501.82, "Apples"], 
 ["Apples", 502.61, "pos2"], 
 ["Apples", 502.61, "pos3"], 
 ["Apples", 502.16, "Apples"]
]

推荐答案

您可以使用

You can use || to handle the undefined.

let input = {
  "Apples": {
    "Apples": 501.82,
    "Apples_pos2": 502.61,
    "Apples_pos3": 502.61,
    "Apples": 502.16,
  }
};

let output = Object.keys(input).reduce((acc, outerKey) => {
  for (let [key, value] of Object.entries(input[outerKey])) {
    acc.push([outerKey, value, key.split('_')[1] || key]);
  }
  return acc;
}, []);

console.log(output);

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