我可以反序列化Json到Python中的C#Newtonsoft之类的类吗 [英] Can I deserialize Json to class like C# Newtonsoft in Python
问题描述
这是json
{"name":"david","age":14,"gender":"male"}
这是python类
class Person:
def __init__(self):
self.name = None
self.age = None
self.gener = None
self.language = None
这是代码
#deserialize func~~~~~
print person.name #prints david
print person.age #prints 14
print person.gender #prints male
print person.language #prints "None"
我可以反序列化Json到Python(例如C#Newtonsoft)中的类
Can I deserialize Json to class in Python(like C# Newtonsoft)
谢谢.
推荐答案
您可以将其与json.loads()
方法一起使用.您还需要确保JSON是一个字符串,而不仅仅是声明为内联.
You can use it with the json.loads()
method. You would also need to ensure your JSON was a string and not just declared inline.
这是一个示例程序:
import json
js = '{"name":"david","age":14,"gender":"male"}'
class Person:
def __init__(self, json_def):
self.__dict__ = json.loads(json_def)
person = Person(js)
print person.name
print person.age
print person.gender
不过,只是一个音符.尝试使用print person.language
时,会出现错误,因为该错误在类中不存在.
Just a note, though. When you attempt to use print person.language
you will have an error, since it doesn't exist on the class.
编辑
如果需要直接映射,则需要对每个可能的对象进行显式映射.
If there is a direct mapping desired, it would require explicit mapping of each possible object.
以下示例将为每个属性提供一个值(如果它存在于JSON对象中),并且还解决了使用任何缺少的属性的愿望:
The following example will give each property a value if it exists in the JSON object and also solves the desire to use any missing properties:
import json
js = '{"name":"david","age":14,"gender":"male"}'
class Person(object):
def __init__(self, json_def):
s = json.loads(json_def)
self.name = None if 'name' not in s else s['name']
self.age = None if 'age' not in s else s['age']
self.gender = None if 'gender' not in s else s['gender']
self.language = None if 'language' not in s else s['language']
person = Person(js)
print person.name
print person.age
print person.gender
print person.language
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