在VB.Net中将JSon转换为动态对象 [英] Convert JSon to dynamic object in VB.Net

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本文介绍了在VB.Net中将JSon转换为动态对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在使用VB.Net并调用salesforce API.它返回非常难看的JSON,我无法反序列化.我有一个使用 JSON.Net

I am using VB.Net and calling salesforce API. It returns very ugly JSON which I am not able to deserialize. I have a following code using JSON.Net

Dim objDescription As Object = JsonConvert.DeserializeObject(Of Object)(result)

objDescription包含许多属性,在fields中一个= f.但是当我写类似objDescription.fields的东西时,它给了我错误.

objDescription contains many properties, one on=f them in fields. But when I write something like objDescription.fields it gives me error.

  objDescription.fields   Public member 'fields' on type 'JObject' not found. Object

我不是很确定,但是我认为C#允许将任何JSON转换为动态对象.如何在VB.Net中使用它?

I am not very sure but I think it C# allow to convert any JSON to dynamic object. How can I use it in VB.Net?

推荐答案

您可以打开Option Strict Off并使用JSON.NET可以识别的ExpandoObject.为了利用动态功能,可以使用object类型的变量.

You can turn Option Strict Off and use ExpandoObject which is recognized by JSON.NET. In order to leverage the dynamic features you can use a variable of type object.

Option Strict Off

Sub Main    
    Dim jsonData As Object = JsonConvert.DeserializeObject(Of System.Dynamic.ExpandoObject)("{""Id"":25}")
    Dim test As Integer = jsonData.Id
    Console.WriteLine(test)
End Sub

如果由于需要JObject的某些功能而希望使用JObject,则可以改为为JObject编制索引.

If you would like to use JObject because you need some of its features, you can index the JObject instead.

Sub Main
    Dim jsonData As Object = JsonConvert.DeserializeObject(Of Object)("{""Id"":25}")
    Dim test = jsonData("Id")
    Console.WriteLine(test)
End Sub

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