在jsonpath中进行过滤时，如何获取第一个元素? [英] How to get the first element when filter in jsonpath?

问题描述

所以我正在研究以下json:

So I'm working on the below json:

{
   "id": "",
   "owner": "some dude",
   "metaData": {
      "request": {
         "ref": null,
         "contacts":[
            {
               "email": null,
               "name": null,
               "contactType": "R"
            },
            {
               "email": null,
               "name": "Dante",
               "contactType": "S"
            }
         ]
      }
   }
}

我要检索的name联系人的类型为S，并且只有第一个返回的联系人.

I want to retrieve the name of contact has type S and only the first one that returned.

使用具有此路径"$..contacts[?(@.contactType == 'S')].name"的jsonpath始终返回字符串数组，因为过滤操作始终将结果作为数组返回.

Using jsonpath with this path "$..contacts[?(@.contactType == 'S')].name" always return an array of string because a filter operation always return result as an array.

所以我尝试了"$..contacts[?(@.contactType == 'S')].name[0]"和"$..contacts[?(@.contactType == 'S')][0].name"，但是没有运气.这些路径返回空结果.

So I tried "$..contacts[?(@.contactType == 'S')].name[0]" and "$..contacts[?(@.contactType == 'S')][0].name" but no luck. Those path returns empty results.

所以我的问题是，在jsonpath中使用filter时，是否有任何方法只能获取第一个元素.我目前正在使用jayway jsonpath v2.2.0.

So my question is, is there any way to get only first element when using filter in jsonpath. I'm currently using jayway jsonpath v2.2.0.

推荐答案

我发现最快的解决方案是将其与列表进行比较，因此在您的情况下是这样的:

The quickest solution I found was just comparing it with a list, so like this in your scenario:

.andExpect(jsonPath("$..contacts[?(@.contactType == 'S')].name", equalTo(Arrays.asList("Dante"))))

(假设您尝试在测试中比较某些结果)

(Assuming you are trying to compare some result in a test of course)

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