使用高阶组件有条件地渲染列表 [英] Conditionally render list with Higher Order Component

问题描述

我的应用程序具有功能切换功能，该功能告诉我的UI是否应渲染一个UI.我想创建一个高阶组件来有条件地呈现这些类型的组件.在一种情况下，我试图有条件地呈现一个列表，但是我遇到了这个错误:

My app has a feature toggle functionality that tells my UI whether or not a piece of UI should be rendered. I would like to create a Higher Order Component to conditionally render these types of components. In one scenario, I'm trying to conditionally render a list, but I'm running into this error:

ConditionalRender(...): A valid React element (or null) must be returned. You may have returned undefined, an array or some other invalid object.

这很有意义，因为我只是尝试渲染此组件的子代.这是到目前为止我得到的:

This makes sense since I just am trying to render the children of this component. Here's what I've got so far:

https://jsfiddle.net/fmpeyton/cykmyabL/

var settings = { showHello: true, showGoodbye: false};

function ConditionalRender (props) {
    var output = null;

  if(props.shouldRender) output = props.children;

  console.log(output);
  // return (<li>{output}</li>); // This works, but isn't desired html structure
  return ({output});
}

function App (props) {
    return (
    <ul>
        <ConditionalRender shouldRender={props.settings.showHello}>
        <li>Hello!</li>
      </ConditionalRender>
      <ConditionalRender shouldRender={props.settings.showGoodbye}>
          <li>Goodbye...</li>
        </ConditionalRender>
    </ul>
  );
}

ReactDOM.render(
  <App settings={settings} />,
  document.getElementById('container')
);

如果我能帮忙的话，我只想在不增加任何逻辑的情况下渲染子代，此HOC还将处理更复杂的子代.像这样:

If I can help it, I would just like to render the children without any additional logic.This HOC would also handle more complex children down the line. Something like this:

<ConditionalRender shouldRender={props.settings.showHello}>
<div>
<p> blah blah blah</p>
<table>
<!-- ... -->
</table>
</div>
</ConditionalRender>

有什么想法吗?

推荐答案

尝试一下:

function App(props) {
  return (
    <ul>        
      {props.settings.showHello && <li>Hello!</li>}
      {props.settings.showGoodbye && <li>Goodbye...</li>}
    </ul>
  );
}

PS .由于此行，您的代码无效:

P.S. Your code doesn't work because of this line:

return ({output});

假设您拥有es2015支持，它将被视为对象属性速记.因此，它与:

Assuming you have es2015 support, it would be treated as object property shorthand. So it's the same as:

return {output: output};

这不是React期望从render方法获得的结果.

which is not what React expects to get from the render method.

您可以尝试以下方法:

function ConditionalRender(props) {
  if (props.shouldRender) {
    // Make sure we have only a single child
    return React.Children.only(props.children);
  } else {
    return null;
  }
}

但这不是最简单的方法.查看更多此处.

But this is not the simplest way. See more here.

P.P.S..ConditionalRender组件不是所谓的高阶组件.根据 docs ，HOC是函数需要一个组件并返回一个新组件.

P.P.S. Your ConditionalRender component is not what is called Higher-Order Component. According to the docs, HOC is a function that takes a component and returns a new component.

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