我怎样才能获得使用Apache HttpClient的自定义内容处置行？ [英] How can I get a custom Content-Disposition line using Apache httpclient?

问题描述

我使用的答案<一个href=\"http://stackoverflow.com/questions/2304663/apache-httpclient-making-multipart-form-post\">here要尽量让与数据上传POST 的要求，但我已经从服务器端的不同寻常的要求。该服务器是一个PHP脚本，它需要一个文件名在内容处置行，因为它是期待一个文件上传

I am using the answer here to try to make a POST request with a data upload, but I have unusual requirements from the server-side. The server is a PHP script which requires a filename on the Content-Disposition line, because it is expecting a file upload.

Content-Disposition: form-data; name="file"; filename="-"

然而，在客户端，我想发布一个内存缓冲区（在这种情况下，一个字符串），而不是一个文件，而是在服务器处理它，就好像是一个文件上传

However, on the client side, I would like to post an in-memory buffer (in this case a String) instead of a file, but have the server process it as though it were a file upload.

但是，在使用上 StringBody 我不能添加所需的文件名字段内容 - 处置行。因此，我试图用 FormBodyPart ，但只是把文件名在单独一行。​​

However, using StringBody I cannot add the required filename field on the Content-Disposition line. Thus, I tried to use FormBodyPart, but that just put the filename on a separate line.

HttpPost httppost = new HttpPost(url);
MultipartEntity entity = new MultipartEntity();
ContentBody body = new StringBody(data,                              
         org.apache.http.entity.ContentType.APPLICATION_OCTET_STREAM);
FormBodyPart fbp = new FormBodyPart("file", body); 
fbp.addField("filename", "-");                     
entity.addPart(fbp);                               
httppost.setEntity(entity);            

我怎样才能得到一个文件名到内容处置行，不先写我的字符串成一个文件，然后回读出来呢？

How can I get a filename into the Content-Disposition line, without first writing my String into a file and then reading it back out again?

推荐答案

试试这个

StringBody stuff = new StringBody("stuff");
FormBodyPart customBodyPart = new FormBodyPart("file", stuff) {

    @Override
    protected void generateContentDisp(final ContentBody body) {
        StringBuilder buffer = new StringBuilder();
        buffer.append("form-data; name=\"");
        buffer.append(getName());
        buffer.append("\"");
        buffer.append("; filename=\"-\"");
        addField(MIME.CONTENT_DISPOSITION, buffer.toString());
    }

};
MultipartEntity entity = new MultipartEntity();
entity.addPart(customBodyPart);

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