Lambda内部的Lambda [英] Lambda inside lambda

问题描述

只是出于好奇.几天前发现了Lambdas.我很想知道是否可以做类似的事情:

Just for curiosity. Discovered Lambdas a few days ago. I was jus wondering if something like that can be done:

(尝试过解释，但我的尝试似乎都无效)

(Tried on the interpret but none of my tries seemed to work)

p = lambda x: (lambda x: x%2)/2

没有明确的目的.我只是找不到满意的答案.我可能误解了Lambda.

There's no explicit purpose. I just did'nt find a satisfactory answer. I may have misunderstood Lambdas.

推荐答案

您实际上不是在呼叫内部lambda:

p = lambda x: (lambda x: x%2)(x)/2

请注意，在Python 2中，此示例将始终返回0，因为除以2的余数将是0或1，并且将结果除以2的整数将导致截断的0.

Note in Python 2 this example will always return 0 since the remainder from dividing by 2 will be either 0 or 1 and integer-dividing that result by 2 will result in a truncated 0.

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