Java Lambda表达式错误 [英] Java Lambda expression error

问题描述

在我的Java 8代码中，

In my Java 8 code,

public ChangePersonsName(String email, final String password, final String wantedUsername, final String uuid, final long time, int latency, int[] requests, int[] proxyRequests) throws IOException {
    final AtomicReference<Object> token = new AtomicReference<Object>();
    final AtomicReference<ArrayList<?>> newHeaders = new AtomicReference<ArrayList<?>>();
    new Thread(() -> {
        boolean lock = true;
        while (lock) {
            if (time - System.currentTimeMillis() > 60000) continue;
            Map<Header[], String> loginResults = null;
            try {
                loginResults = this.login(email, password, uuid);
            }
            catch (IOException e) {
                e.printStackTrace();
            }
           String token = loginResults.entrySet().iterator().next().getValue();
            Header[] headers = loginResults.entrySet().iterator().next().getKey();
            newHeaders.set(new ArrayList<Object>());
            for (Header header : headers) {
                if (!header.toString().startsWith("Set-Cookie:")) continue;
                ((List<BasicHeader>)newHeaders.get()).add(new BasicHeader("Cookie", header.toString().split("Set-Cookie: ")[1]));
            }
            lock = false;
        }
    }
    ).start();
    new Timer().schedule(new TimerTask(){

您会注意到

String token = loginResults.entrySet().iterator().next().getValue(); 

引发编译错误，

Lambda表达式的局部变量标记不能重新声明在封闭范围内定义的另一个局部变量.

Lambda expression's local variable token cannot redeclare another local variable defined in an enclosing scope.

我的问题是，如何解决这个问题?我对Java很陌生，我可能应该知道如何解决这个问题，但是我不知道.

My question is, How would one go about fixing this? I'm pretty new to Java, I should probably know how to fix this, but i don't.

推荐答案

在此范围内，您已经具有名称为token的变量.您已经在第二行中声明了它.要修复，只需重命名第二个变量:

You already have variable with name token in this scope. You've declared it in 2nd row. To fix just rename 2nd variable:

String newToken = loginResults.entrySet().iterator().next().getValue(); 

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