将带有lambda的元组解包从Python 2移植到Python 3的大多数pythonic方式 [英] Most pythonic way to port this tuple unpacking with lambda from Python 2 into Python 3

问题描述

我有以下Python 2代码，用于在lambda内部解压缩元组.该lambda包含在for循环中.

I have the following Python 2 code which unpacks a tuple inside a lambda. This lambda is contained inside a for loop.

    for lab, lab_pred, length in zip(labels, labels_pred, sequence_lengths):
        accs += map(lambda (a, b): a == b, zip(lab, lab_pred))

将其移植到Python 3中的最佳方法是什么?

What is the best way to port this into Python 3?

推荐答案

我认为最好的解决方案是不使用map和lambda，而是使用列表理解:

I think the best solution would be to not use map and lambda, use a list comprehension instead:

accs += [a == b for a, b in zip(lab, lab_pred)]

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