在C#中,如果未将类或方法标记为密封的或虚的,那是什么? [英] In C#, if a class or a method is not marked as sealed or virtual, what is it?
问题描述
换句话说,默认值是什么(如果未指定任何内容)?我猜默认值是虚拟的,因为即使没有指定虚拟方法,也可以使用"new"关键字来覆盖基本方法.如果是这样,那为什么我们甚至需要虚拟选项?当我们需要阻止进一步的继承时,我们是否只能使用Sealed?
In other words, what's the default (if nothing is specified)? I'm guessing the default is virtual, because you can use the "new" keyword to override a base method even when the base method has no virtual specified. If that's the case then why do we even need a Virtual option? Couldn't we just use Sealed when we do need to prevent further inheritance?
推荐答案
默认情况下,C#方法是密封的-如果没有 virtual
关键字,则无法覆盖它们.
C# methods are sealed by default -- you cannot override them without the virtual
keyword.
new
关键字隐藏基类中的方法.
The new
keyword hides the method in the base class.
这就是我隐藏的意思:
public class HidingA
{
public string Get()
{
return "A";
}
}
public class HidingB : HidingA
{
public new string Get()
{
return "B";
}
}
HidingA a = new HidingA();
HidingB b = new HidingB();
Console.WriteLine(a.Get()); // "A"
Console.WriteLine(b.Get()); // "B"
HidingA c = new HidingB();
Console.WriteLine(c.Get()); // "A". Since we're calling this instance of "B" an "A",
//we're using the "A" implementation.
现在,虚拟版本!
public class VirtualA
{
public virtual string Get()
{
return "A";
}
}
public class VirtualB : VirtualA
{
public override string Get()
{
return "B";
}
}
VirtualA a = new VirtualA();
VirtualB b = new VirtualB();
Console.WriteLine(a.Get()); // "A"
Console.WriteLine(b.Get()); // "B"
VirtualA c = new VirtualB();
Console.WriteLine(c.Get()); // "B". We overrode VirtualB.Get, so it's using the
// "B" implementation of the method
因此,如果我们采用以 HidingA
作为参数并将其传递为 HidingB
的实例的方法,我们将获得 HidingA
Get
方法的实现.
So if we make a method that takes HidingA
as a parameter and pass it an instance of a HidingB
, we're going to get the HidingA
implementation of the Get
method.
MSDN: http://msdn.microsoft.com/zh-cn/library/6fawty39.aspx
除非指定 sealed
关键字,否则打开类进行继承.
Classes are open for inheritance unless the sealed
keyword is specified.
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