如何从C#中的xml读取特定节点? [英] How to read a particular node from xml in C#?

问题描述

我有以下XML:

<Loop Name="MasterData">
  <Loop Name="SlaveData">
    <Segment Name="AAA">
      <Node1>hello</Node1>
      <Node2>john</Node2>
      <Node3>hi</Node3>
      <Node4>marry</Node4>
    </Segment>
    <Segment Name="BBB">
      <Node1>00</Node1>
      <Node2> </Node2>
      <Node3>00</Node3>
      <Node4> </Node4>
    </Segment> 
   </Loop>
</Loop>

我必须读取位于属性为 Name ="AAA" 的Segment节点下的每个Node的值，即Node1，Node2，Node3，Node4.我怎样才能做到这一点.我指的是来自stackoverflow的以下链接，但这对我不起作用.

I have to read value of each Node i.e, Node1, Node2, Node3, Node4 which are under Segment node whose attribute ie Name = "AAA". How can I do this. I am referring following link from stackoverflow but thats not working for me.

如何从C#中的XmlNode读取属性值?/a>

How to read attribute value from XmlNode in C#?

我需要这样的输出

让我有四个字符串变量 strNode1，strNode2，strNode3，strNode4 .我想将值存储在以下四个变量中

Lets I have four sting variables strNode1, strNode2, strNode3, strNode4. I want to store values in above four variables like following

strNode1 = "hello"
strNode2 = "john"
strNode3 = "hi"
strNode4  = "marry"

推荐答案

我找到了解决问题的简单方法

I found a simple solution for my problem

XmlNodeList xnList = doc.SelectNodes("/Loop/Loop/Segment[@Name='AAA']");
          foreach (XmlNode xn in xnList)
          {
              if (xn.HasChildNodes)
              {
                  foreach (XmlNode item in xn.ChildNodes)
                  {
                      Console.WriteLine(item.InnerText);
                  }
              }  
          }

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