无法在PowerShell中将字符串转换为int [英] Can't convert string to int in PowerShell
问题描述
我正在尝试使用PowerShell将字符串转换为整数.但是，即使我确定知道，我仍然会告诉我我没有有效的电话号码.
I'm attempting to convert a string to an integer using PowerShell. However, it keeps on telling me that I don't have a valid number, even though I'm sure I do.
首先，这是我获取变量的方式以及类型的打印输出等，只是为了确保有效性:
First of all, here's how I'm getting my variable, and a printout of the type, etc. just to ensure validity:
$obj = (New-Object -TypeName PSCustomObject -Property @{
LastSaved = $com.GetDetailsOf($_, 155).toString().trim()
})
Write-Host $obj.LastSaved
$datePart,$b,$c = $obj.LastSaved.Split(" ")
Write-Host $datePart
$intVar,$b,$c = $datePart.Split("/")
$intVar = $intVar.Trim()
$intVar -replace '\W', ''
Write-Host $intVar
Write-Host $intVar.GetType()
输出:
5/26/2016上午8:09
5/26/2016 8:09 AM
5/26/2016
5/26/2016
5
System.String
System.String
这是我尝试进行转换的第一个方法:
Here's the first method I've tried for conversion:
[int]$converted = 0
[int]::TryParse($intVar, [ref]$converted)
Write-Host $converted
输出:
错误
0
下一个方法:
$converted = [convert]::ToInt32($intVar, 10)
结果:
异常调用"ToInt32"；带有"2"的参数:找不到任何可识别的数字."
Exception calling "ToInt32" with "2" argument(s): "Could not find any recognizable digits."
还有我尝试过的第三种方法:
And the third method I've tried:
$converted = $intVar / 1
结果:
无法转换值"5"；键入"System.Int32".错误:输入字符串的格式不正确."
Cannot convert value "5" to type "System.Int32". Error: "Input string was not in a correct format."
如果我手动分配 $ intVar 值为"5"，( $ intVar ="5" )一切都很好，所以我认为如何获取价值肯定存在问题.但是我不知道该怎么做，因为 GetType()说它确实是一个字符串.
If I manually assign $intVar a value of "5" ($intVar = "5") everything works just fine, so I think there must be an issue with how I'm getting the value. But I have no idea what I could be doing wrong, as the GetType() says it is indeed a string.
编辑:根据TobyU的回答，我还尝试过 $ intVar = [int] $ intVar ，结果相同
Per TobyU's answer, I've also tried $intVar = [int]$intVar, with the same result of
无法转换值"5"；键入"System.Int32".错误:输入字符串的格式不正确."
Cannot convert value "5" to type "System.Int32". Error: "Input string was not in a correct format."
还有另一种方法:
$ intVar = [int] :: Parse($ intVar)
哪个给:
异常调用解析"；带有"1"的参数:输入字符串的格式不正确."
Exception calling "Parse" with "1" argument(s): "Input string was not in a correct format."
显然，正如一些评论者所述，其中包含无效字符.这是 Format-Hex 的输出:
EDIT 3: So apparently, as some commenters mentioned, there are invalid characters. Here is the output of a Format-Hex:
00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
00000000 3F 32 36 ?26
推荐答案
Examining the error messages in your question's source text reveals that your string contains the invisible LEFT-TO-RIGHT-MARK Unicode character (U+200E), which is why the conversion fails.
删除该字符将使转换成功，在最简单的情况下，这是通过简单地消除所有非数字字符来实现的.从字符串中:
Removing that character will make the conversion succeed, which in the simplest case is achieved by simply eliminating all non-digit chars. from the string:
# Simulate the input string with the invisible control char.
$intStr = [char] 0x200e + '5'
# FAILS, due to the invisible Unicode char.
[int] $intStr # -> ... "Input string was not in a correct format."
# OK - eliminate non-digits first.
# Note the required (...) for proper precedence.
[int] ($intStr -replace '\D') # -> 5
可选阅读:检查字符串的字符:
# Print the code points of the string's characters:
PS> [int[]] [char[]] $intStr
8206 # decimal equivalent of 0x200e, the LEFT-TO-RIGHT-MARK
53 # decimal equivalent of 0x54, the DIGIT FIVE
# Show the code points in hex. format and print the char.
PS> [char[]] $intStr |
Select-Object @{ n='CodePoint'; e={ 'U+{0}' -f ([int] $_).ToString('X4') } },
@{ n='Char'; e={ $_ } }
CodePoint Char
--------- ----
U+200E
U+0035 5
您也可以使用 Format-Hex ，但是格式不易以视觉方式解析:
You can also use Format-Hex, but the format isn't easy to parse visually:
PS> $intStr | Format-Hex -Encoding BigEndianUnicode
00 01 02 03 04 05 06 07 08 09 0A 0B 0C 0D 0E 0F
00000000000000000000 20 0E 00 35 ..5
使用
-编码BigEndianUnicode (UTF16-BE)-即使.NET字符串使用 Unicode (UTF16-LE)-因此， byte <面向/em>的显示屏首先显示16位代码单元的高字节，这样读取起来更自然.
-Encoding BigEndianUnicode (UTF16-BE) is used - even though .NET string use Unicode (UTF16-LE) - so that the invariably byte-oriented display shows the high byte of the 16-bit code units first, which reads more naturally.
字节对 20 0E 是第一个代码单元， U + 200E (从左到右的标记)和 00 35 第二个是 U + 0035 (数字 5 ).
Byte pair 20 0E is the first code unit, U+200E (the left-to-right mark), and 00 35 the second one, U+0035 (the digit 5).
右侧打印的字符用途有限，因为它们是输入字节的 byte 单个解释，只能解释预期的8位范围内的字符(代码点<; = U + 00FF ); 0x0 字节表示为.
The printed characters to the right are of limited usefulness, because they are the byte-individual interpretation of the input bytes, which only renders characters in the 8-bit range as expected (code points <= U+00FF); a 0x0 byte is represented as a .
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