启动进程后获取友好名称 [英] Getting the friendly name for a Process after starting it

问题描述

我正在为嵌入式系统的看门狗服务编写代码，该服务监视一些专有进程并在必要时重新启动它们.(在您问之前，与恶意软件无关.这只是一项业务要求)

I'm coding a watchdog service for an embedded system that monitors some proprietary processes and restarts them if necessary. (Nothing to do with malware, before you ask. It's just a business requirement)

我需要从刚刚创建的进程中检索友好名称，以便以后可以使用该名称检索该进程以监视其运行状况.

I need to retrieve the friendly name from a process I have just created, so that later I can retrieve that process using that name in order to monitor its health.

我的问题如下:

• 如果我尝试在 Process.Start()之后立即读取 Process.ProcessName ，则会收到 InvalidOperationException ，因为它流程尚未完全创建.

• If I try to read Process.ProcessName right after Process.Start(), I get an InvalidOperationException because it the process has not been fully created yet.

如果我使用 Process.WaitForInputIdle()，也会发生同样的情况，但是由于这需要消息泵，并且许多可执行文件可能是实际应用程序的无UI启动器，因此可能不是一个选项.

The same happens if I use Process.WaitForInputIdle(), but since this requires a message pump and many executables could be UI-less launchers for the actual application, this might not be an option.

我需要在创建过程之后立即进行操作，然后再进行其他操作.

I need to get the friendly name right after creating the process, before doing anything else.

这是一个代码段:

var startInfo = new ProcessStartInfo { FileName = "notepad.exe" };
var process = new Process();
process.StartInfo = startInfo;
process.Start();
process.WaitForInputIdle();
var friendlyName = process.ProcessName;

例如，如果正在启动的进程是Firefox，则会在最后一行抛出 InvalidOperationException .

This will throw an InvalidOperationException on the last line if the process being started is Firefox, for example.

那我该怎么做?有没有更安全的方法?

So how would I do this? Is there a safer method?

添加了一个代码段以进行澄清.重新解释整个问题以便澄清，将无关紧要的内容排除在外.

Added a code snippet for clarification. Rephrased the whole question for clarification, left irrelevant stuff out.

推荐答案

好，因此，经过大量研究，我不得不求助于有些棘手的解决方案.

Ok, so after a lot of research I had to resort to a somewhat hacky solution.

根据 Process.GetProcessesByName()文档，"进程名称是该进程的友好名称，例如Outlook，不包含.exe扩展名或路径.".

考虑到这一点，我使用以下代码解决了该问题:

Considering this, I worked around the problem using this code:

var startInfo = new ProcessStartInfo { FileName = "notepad.exe" };
var process = new Process();
process.StartInfo = startInfo;
process.Start();
var friendlyName = Path.GetFileNameWithoutExtension(startInfo.FileName);

就像我说的那样，它仍然有点怪异，但至少完成了工作并让我继续前进.

As I said, it still feels kinda hacky, but at least it got the job done and allowed me to move on.

仍然感谢您的所有评论！

Thanks for all your comments anyway!

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