readyState 4-可以重定向网址吗? [英] readyState 4 - redirect url is that possible?

问题描述

我想知道当你有readyState == 4时是否有可能重定向到页面.

I was wondering if it is possible when u have readyState == 4, to redirect to a page..

    //load the send form
    if (sendRequest) {
        sendRequest.open("POST", urlRequest, true);
        sendRequest.setRequestHeader("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8");
        sendRequest.setRequestHeader("Connection", "close");
        sendRequest.onreadystatechange = displayStatus;
        sendRequest.send(sendData);
    } else {
        alert("fails"); //alert if request fails
    }
}

function displayStatus() {
    if (sendRequest.readyState == 4) {
        alert("send");
    // redirect to thank you page? 


    } else {
        alert("send fails"); 

} //end readyState

}

我不会得到200

所以在readyState 4上，我想重定向到页面，发送表格后，我想重定向到页面.在php邮件功能上，<?php标头(位置:"url")；?> 不起作用所以我真的需要在ajax/javascript中使用它...

so on readyState 4 , i want to redirect to a page, after the form is sended i want to redirect to a page. on php mail function, <?php header(location: "url"); ?> is not working so i really need to have it in ajax/javascript...

目前，它只是无法正常工作.有什么建议吗?

currently it just not working. any suggestion?

推荐答案

谢谢J.Romero.通过您的输入，我已经找到了问题所在，并构造了一些不同的脚本.

Thank you J.Romero. With your input i have trace down the problem and construct the script a bit different.

这不是跨域问题-正确设置了这些设置.警报框是正确的，并且sendRequest是全局的，因此所有函数都可以调用它.

It was not a cross domain issue - those settings are set properly. Alert box is correct and the sendRequest is global, so all functions can call it.

这仅导致1条故障，形式为.有 onSubmit ="return checkForm(this);"action =" 它应该是 onSubmit ="checkForm(this);返回false;"action ="

This lead to only 1 fault, and that is in the form. had onSubmit="return checkForm(this);" action="" It should be onSubmit="checkForm(this); return false;" action=""

与onSubmit事件一起返回的值为false，因此该表单不会像往常一样提交.并正确构建js和ajax以完成发送表单.验证表单->确定->准备表单->调用ajax->所有有效->发送表单->重定向到谢谢"页面.

with the onSubmit event return a value of false, so the form doesn't submit as usual. and constructing the js and ajax properly to finalize the send form. validate the form -> when ok -> prepare the form -> call ajax -> all valid -> send form -> redirect to thank you page.

谢谢大家的帮助！

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