反向波兰语符号C#无法正常工作 [英] Reverse polish notation C# don't work correctly

问题描述

我写了一个带有结构图的rpn.

I write an rpn, with a struktogram.

最新问题:目前无法正常工作.

Newest Problem: It is'nt work correctly now.

如果输入字符串为"5 +((1 + 2)* 4)-3"

If input string is "5 + ((1 + 2) * 4) - 3"

我的输出是:5 1 2 + 4 * 3-+

My output is: 5 1 2 + 4 * 3 - +

我必须得到以下结果:5 1 2 + 4 * + 3-

I have to got this result: 5 1 2 + 4 * + 3 -

编辑了源文件

* 这是最初的问题，但对我有帮助，现在修复了最初的错误:* ，

在调试时循环或 int i = 12，c值为0 \ 0或其他值 然后将此值作为("括号添加到输出(名称:公式)字符串中.我不知道为什么.最后一个'-'运算符，不要添加到(或不看)在输出字符串的末尾(公式)我误认为是由'('引起的.我用其他字符串输入值尝试了该程序，但始终在字符串中加上'('，但我不知道为什么...我看到它与括号的数量无关.总是只有一个'('添加到我的字符串中... *)是的，英语为LengyelFormula = rpn(匈牙利语)*

At the debug when the loop or int i = 12, the c value is 0\0 or something else and this value is added to output (name: formula) string as a '(' bracket. And I don't know why. And the last '-' operation symbol, don't added to (or not look) at the end of output string (formula) I misgave this problem cause by the '('. I tried the program with other string input value, but always put an '(' to my string, and I don't know why... I saw that It was independt about the numbers of bracket. Always only one '(' add to my string...*) Yes, in english LengyelFormula = rpn (it is hungarian)*

static void Main(string[] args)
    {
        String str = "5 + ( ( 1 + 2 ) *  4 ) −3";
        String result=LengyelFormaKonvertalas(str);
        Console.WriteLine(result.ToString());
        Console.ReadLine();
    }

    static String LengyelFormaKonvertalas(String input) // this is the rpn method
    {
       Stack stack = new Stack();
       String str = input.Replace(" ",string.Empty);
       StringBuilder formula = new StringBuilder();
       for (int i = 0; i < str.Length; i++)
       {
           char x=str[i];
           if (x == '(')
               stack.Push(x);
           else if (IsOperandus(x)) // is it operand
           {
               formula.Append(x);
           }
           else if (IsOperator(x))  // is it operation
           {
               if (stack.Count>0 && (char)stack.Peek()!='(' && Prior(x)<=Prior((char)stack.Peek()) )
               {
                   char y = (char)stack.Pop();
                   formula.Append(y);
               }
               if (stack.Count > 0 && (char)stack.Peek() != '(' && Prior(x) < Prior((char)stack.Peek()))
               {
                   char y = (char)stack.Pop();
                   formula.Append(y);
               }
               stack.Push(x);
           }
           else
           {
              char y=(char)stack.Pop();
              if (y!='(')
              {
                  formula.Append(y);
              }
           }
       }
       while (stack.Count>0)
       {
           char c = (char)stack.Pop();
           formula.Append(c);
       }
       return formula.ToString();
    }

    static bool IsOperator(char c)
    {
        return (c=='-'|| c=='+' || c=='*' || c=='/');
    }
    static bool IsOperandus(char c)
    {
        return (c>='0' && c<='9' || c=='.');
    }
    static int Prior(char c)
    {
        switch (c)
        {
            case '=':
                return 1;
            case '+':
                return 2;
            case '-':
                return 2;
            case '*':
                return 3;
            case '/':
                return 3;
            case '^':
                return 4;
            default:
                throw new ArgumentException("Rossz paraméter");                                          
        }
    }
}

推荐答案

using System;
using System.Collections.Generic;
using System.Text;

class Sample {
    static void Main(string[] args){
        String str = "5 + ( ( 1 + 2 ) *  4 ) -3";
        String result=LengyelFormaKonvertalas(str);
        Console.WriteLine(result);
        Console.ReadLine();
    }

    static String LengyelFormaKonvertalas(String input){
       Stack<char> stack = new Stack<char>();
       String str = input.Replace(" ", string.Empty);
       StringBuilder formula = new StringBuilder();
       for (int i = 0; i < str.Length; i++){
           char x=str[i];
           if (x == '(')
               stack.Push(x);
           else if (x == ')'){
               while(stack.Count>0 && stack.Peek() != '(')
                   formula.Append(stack.Pop());
               stack.Pop();
           } else if (IsOperandus(x)){
               formula.Append(x);
           } else if (IsOperator(x)) {
               while(stack.Count>0 && stack.Peek() != '(' && Prior(x)<=Prior(stack.Peek()) )
                   formula.Append(stack.Pop());
               stack.Push(x);
           }
           else {
              char y= stack.Pop();
              if (y!='(') 
                  formula.Append(y);
           }
       }
       while (stack.Count>0) {
           formula.Append(stack.Pop());
       }
       return formula.ToString();
    }

    static bool IsOperator(char c){
        return (c=='-'|| c=='+' || c=='*' || c=='/');
    }
    static bool IsOperandus(char c){
        return (c>='0' && c<='9' || c=='.');
    }
    static int Prior(char c){
        switch (c){
            case '=':
                return 1;
            case '+':
                return 2;
            case '-':
                return 2;
            case '*':
                return 3;
            case '/':
                return 3;
            case '^':
                return 4;
            default:
                throw new ArgumentException("Rossz parameter");                                          
        }
    }
}

这篇关于反向波兰语符号C#无法正常工作的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！